Chapter 1: Problem 28
Graph each function "by hand." [Note: Even if you have a graphing calculator, it is important to be able to sketch simple curves by finding a few important points.] $$ f(x)=3 x^{2}-6 x-9 $$
Short Answer
Expert verified
Sketch a parabola with vertex (1, -12), axis x=1, and passes through points (0, -9), (2, -9), (-1, -6).
Step by step solution
01
Identify the Type of Function
The given function is \( f(x) = 3x^2 - 6x - 9 \), which is a quadratic function, identifiable by its general form \( ax^2 + bx + c \). This type of function graphs into a parabola.
02
Find the Vertex
To find the vertex of the parabola, use the formula \( x = -\frac{b}{2a} \). Here, \( a = 3 \) and \( b = -6 \). Calculate \( x = -\frac{-6}{2 \times 3} = 1 \). Substitute \( x = 1 \) back into the function to find \( f(1) = 3(1)^2 - 6(1) - 9 = -12 \). Therefore, the vertex is \((1, -12)\).
03
Determine the Axis of Symmetry
The axis of symmetry for the parabola is the vertical line that passes through the vertex. Since the vertex is at \( x = 1 \), the axis of symmetry is \( x = 1 \).
04
Find the Y-intercept
The y-intercept is the point where the graph intersects the y-axis (when \( x = 0 \)). Substitute \( x = 0 \) into the function: \( f(0) = 3(0)^2 - 6(0) - 9 = -9 \). So, the y-intercept is \((0, -9)\).
05
Find Additional Points by Choosing X-values
Choose x-values around the vertex to calculate additional points for the curve. For example, for \( x = 2 \), calculate \( f(2) = 3(2)^2 - 6(2) - 9 = -9 \), so \((2, -9)\) is another point. Similarly, for \( x = -1 \), \( f(-1) = 3(-1)^2 - 6(-1) - 9 = -6 \), so \((-1, -6)\) is another point.
06
Plot Points and Sketch the Parabola
On a Cartesian plane, plot the vertex \((1, -12)\), y-intercept \((0, -9)\), and additional points \((2, -9)\) and \((-1, -6)\). Draw a smooth curve through the points to form a parabola, ensuring it opens upwards as the coefficient of \( x^2 \) is positive.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
In mathematics, a parabola is a symmetric, U-shaped curve that represents the graph of a quadratic function. A parabolic curve is always open, either upwards or downwards, depending on the coefficient of the squared term in the quadratic equation.
In a standard quadratic function form, such as \( ax^2 + bx + c \), the parabola opens upward if \( a > 0 \) and downward if \( a < 0 \).
In a standard quadratic function form, such as \( ax^2 + bx + c \), the parabola opens upward if \( a > 0 \) and downward if \( a < 0 \).
- The basic shape of a parabola is determined by the term \( ax^2 \).
- The parabola is symmetrical about a vertical line, known as the axis of symmetry.
- Parabolas appear in various real-world contexts, such as the trajectory of a tossed ball or the design of satellite dishes.
Vertex
The vertex of a parabola is a significant point that represents the highest or lowest point of the curve. For upward-opening parabolas, the vertex is the minimum point, while for downward-opening parabolas, it is the maximum.
To find the vertex of a parabola represented by the quadratic function \( f(x) = ax^2 + bx + c \), use the formula: \[ x = -\frac{b}{2a}, \]which calculates the x-coordinate of the vertex.
Once the x-coordinate is determined, substitute it back into the equation to find the corresponding y-coordinate, completing the vertex coordinates \((x, y)\).
To find the vertex of a parabola represented by the quadratic function \( f(x) = ax^2 + bx + c \), use the formula: \[ x = -\frac{b}{2a}, \]which calculates the x-coordinate of the vertex.
Once the x-coordinate is determined, substitute it back into the equation to find the corresponding y-coordinate, completing the vertex coordinates \((x, y)\).
- The vertex gives valuable information about the parabola's location and orientation.
- It is often used as a reference point when sketching the parabola.
Axis of Symmetry
The axis of symmetry of a parabola is a vertical line that divides the parabola into two mirror-image halves. It plays a crucial role in the symmetrical nature of parabolas and can be derived directly from the vertex.
The axis of symmetry for a quadratic function \( f(x) = ax^2 + bx + c \) is given by the line:\[ x = -\frac{b}{2a}\]This line always passes through the vertex of the parabola.
The axis of symmetry for a quadratic function \( f(x) = ax^2 + bx + c \) is given by the line:\[ x = -\frac{b}{2a}\]This line always passes through the vertex of the parabola.
- Points on the parabola that are equidistant from the axis of symmetry will have identical y-values.
- Finding the axis of symmetry helps in predicting the shape and position of the entire parabola.
Y-intercept
The y-intercept of a parabola is the point where the curve intersects the y-axis. This point provides a starting location on the graph and is essential for sketching simple curves accurately. To find the y-intercept of a quadratic function \( f(x) = ax^2 + bx + c \), substitute \( x = 0 \) into the equation: \[ f(0) = c\]This calculation reveals that the y-intercept is precisely \((0, c)\).
Understanding the y-intercept:
Understanding the y-intercept:
- The y-intercept remains constant for the given quadratic function unless shifts occur in transformations.
- It acts as an initial point of reference when plotting the parabola by hand.