Chapter 1: Problem 23
For each equation, find the slope \(m\) and \(y\) intercept \((0, b)\) (when they exist) and draw the graph. \(2 x-3 y=12\)
Short Answer
Expert verified
The slope is \(\frac{2}{3}\) and the y-intercept is \((0, -4)\).
Step by step solution
01
Transform to Slope-Intercept Form
The slope-intercept form of an equation is given by \(y = mx + b\). To find the slope \(m\) and \(y\)-intercept \((0, b)\), we need to rewrite the equation \(2x - 3y = 12\) in this form. Start by solving for \(y\):\[ 2x - 3y = 12 \]Subtract \(2x\) from both sides to isolate \(-3y\):\[ -3y = -2x + 12 \]Divide every term by \(-3\):\[ y = \frac{2}{3}x - 4 \]Now, it is in the form \(y = mx + b\) with \(m = \frac{2}{3}\) and \(b = -4\).
02
Identify Slope and Y-Intercept
From the transformed equation \(y = \frac{2}{3}x - 4\), identify the slope \(m\) and the y-intercept \(b\). The slope \(m\) is \(\frac{2}{3}\), indicating that for each increase of 3 in \(x\), \(y\) increases by 2. The y-intercept \((0, b)\) is \( (0, -4)\), which is the point where the line crosses the y-axis.
03
Graph the Equation
To graph the equation, begin by plotting the y-intercept on the y-axis at the point \((0, -4)\). From this point, use the slope \(\frac{2}{3}\) to find another point on the line: move up 2 units and 3 units to the right, reaching \((3, -2)\). Connect these points with a straight line to visualize the graph. Make sure to continue the line in both directions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of a Line
Understanding the equation of a line is key in algebra. A linear equation in two variables, such as \(2x - 3y = 12\), can be represented in different forms. The most adaptable form is the slope-intercept form, \(y = mx + b\). Here, \(m\) represents the slope of the line, while \(b\) is the y-intercept, where the line crosses the y-axis.Let's start by manipulating the original equation, \(2x - 3y = 12\). To write it in slope-intercept form, solve for \(y\). This might require rearranging the terms, isolating \(y\) on one side of the equation.
- Subtract \(2x\) from both sides: \(-3y = -2x + 12\)
- Divide every term by \(-3\) to solve for \(y\): \(y = \frac{2}{3}x - 4\)
Graphing Linear Equations
Graphing linear equations allows us to visually represent algebraic relationships between variables. Let's look at the equation \(y = \frac{2}{3}x - 4\). This is an example of a linear equation where the graph will be a straight line.To graph this equation:
- First, identify the y-intercept \((0, b)\). In our equation, \(b = -4\), so the y-intercept is at \( (0, -4)\).
- Plot this point on the graph as it shows where the line crosses the y-axis.
- Next, use the slope \(\frac{2}{3}\) to find another point. The slope tells us that for every 3 units moved horizontally to the right, the vertical change is 2 units up. Start from \( (0, -4)\), move 3 units to the right and 2 units up to reach the next point \( (3, -2)\).
Slope and Y-Intercept
The slope and y-intercept are essential components in defining the characteristics of a line in the slope-intercept form, \(y = mx + b\).
Slope
The slope, indicated by \(m\), determines the steepness and direction of the line. Positive slopes rise when moving left to right, while negative slopes fall. In our equation \(y = \frac{2}{3}x - 4\), the slope \(\frac{2}{3}\) means:- For every increase of 3 units in \(x\), \(y\) increases by 2 units.
- The line rises gently compared to a steeper slope like \(2x\) (which would rise 2 units for every single unit increased in \(x\)).