Chapter 13: Problem 10
Prove that if \(\left\\{a_{n}\right\\}\) converges to \(L\) and \(\left\\{b_{n}\right\\}\) converges to \(M,\) then the sequence \(\left\\{a_{n}+b_{n}\right\\}\) converges to \(L+M\)
Short Answer
Expert verified
The sequence \(\left\{a_{n}+b_{n}\right\}\) converges to \(L+M\).
Step by step solution
01
Understand the Definition of Convergence
First, it is important to understand what it means for a sequence to converge. A sequence \(\left\{a_{n}\right\}\) is said to converge to \(L\) if, for every positive real number \(\epsilon > 0\), there exists a natural number \(N\) such that for all \(n>N\), the absolute value \(|a_{n}-L| < \epsilon\). Similarly for the sequence \(\left\{b_{n}\right\}\) converging to \(M\).
02
Apply Definition to Both Sequences
Given that \(\left\{a_{n}\right\}\) converges to \(L\) and \(\left\{b_{n}\right\}\) converges to \(M\), for every \(\epsilon > 0\), there exist natural numbers \(P\) and \(Q\) such that for all \(n>P\) we have \(|a_{n}-L| < \frac{\epsilon}{2}\) and for all \(n>Q\) we have \(|b_{n}-M| < \frac{\epsilon}{2}\). Choose \(N = \max\{P, Q\}\).
03
Combine and Show New Sequence Convergence
We consider the sequence \( \left\{a_{n}+b_{n}\right\}\). For all \(n>N\), we have \(|(a_{n}+b_{n})-(L+M)| = |(a_{n}-L)+(b_{n}-M)| \leq |a_{n}-L|+|b_{n}-M| < \frac{\epsilon}{2} + \frac{\epsilon}{2} = \epsilon\). Thus, the sequence \(\left\{a_{n}+b_{n}\right\}\) converges to \(L+M\).
04
Summarize The Conclusion
In conclusion, if a sequence \(\left\{a_{n}\right\}\) converges to \(L\) and another sequence \(\left\{b_{n}\right\}\) converges to \(M,\) then the sequence formed by the term-wise sum, \(\left\{a_{n}+b_{n}\right\}\), converges to the sum of the limits, \(L+M\). This is often referred to as the sum rule for convergent sequences.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sequence Convergence
Sequence convergence is a fundamental concept in calculus and analysis. When we say a sequence converges, we mean that as you go further and further along the sequence, the numbers in the sequence get closer and closer to a specific value, called the limit. This process is like traveling along a path that ends at a target point. For the sequence \(\{a_{n}\}\) to converge to a limit \(L\), we need:
- For any small positive number \(\epsilon\), there exists a point in the sequence after which all terms are within \(\epsilon\) of \(L\).
- If you choose a neighborhood around \(L\) (within \(\epsilon\)), the terms of the sequence eventually stay inside this neighborhood.
Sum Rule
The sum rule for sequences is a handy tool for combining convergent sequences. It states that if you have two sequences \(\{a_{n}\}\) and \(\{b_{n}\}\), where each one individually converges to a limit \(L\) and \(M\) respectively, then the sequence formed by adding their corresponding terms, \(\{a_{n} + b_{n}\}\), will converge to \(L + M\).
This rule follows from the arithmetic properties of limits, where you can distribute limits over sums. Here's why:
This rule follows from the arithmetic properties of limits, where you can distribute limits over sums. Here's why:
- Both sequences approach their respective limits as \(n\) grows larger.
- Adding the small differences \(|a_{n} - L|\) and \(|b_{n} - M|\) results in a value that's also small, which ensures \(|a_{n} + b_{n} - (L + M)|\) remains small.
Definition of Convergence
Understanding the definition of convergence is crucial to grasping how sequences behave as they progress. To say that a sequence \(\{a_{n}\}\) converges to a limit \(L\), mathematically means:
- For every \(\epsilon > 0\), there must be some natural number \(N\) such that anytime the sequence vertex \(n\) is greater than \(N\), the terms \(a_{n}\) remain within this tolerance \(\epsilon\) around \(L\).
- Said simply, after a certain point, all terms of the sequence are locked in a close range from \(L\).