Chapter 8: Problem 24
$$\begin{array}{l}{\text { If a child pulls a sled through the snow on a level path with }} \\ {\text { a force of } 50 \mathrm{N} \text { exerted at an angle of } 38^{\circ} \text { above the hori- }} \\ {\text { zontal, find the horizontal and vertical components of the }} \\ {\text { force }}\end{array}$$
Short Answer
Step by step solution
Understand the Problem
Identify the Components
Calculate the Horizontal Component
Perform the Calculation for Horizontal Component
Calculate the Vertical Component
Perform the Calculation for Vertical Component
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Horizontal Component
To figure out what chunk of the force actually pulls the sled along the ground, trigonometry comes in handy. By using the cosine function, which relates to the horizontal in trigonometry, we can express the horizontal component of the force (\( F_x \)) as \( F_x = F \cdot \cos(\theta) \). Here:
- \( F \) is the total force applied, which is 50 N in this case.
- \( \theta \) is the angle between the force and the horizontal line, 38 degrees here.
This means out of the total 50 N, about 39.4 N is effectively used in moving the sled horizontally.
Vertical Component
In this case, the sine function is our go-to tool. The vertical component (\( F_y \)) can be calculated as \( F_y = F \cdot \sin(\theta) \). This tells us:
- \( F \): The entire amount of the applied force remains 50 N.
- \( \theta \): This angle between force direction and horizontal is 38 degrees.
This implies that out of the total force, about 30.8 N acts in a direction that has no influence on moving the sled horizontally but could slightly lift or press it down into the snow.
Trigonometry in Physics
- **Decomposition of Forces**: Many physical situations involve forces that don’t act perfectly along standard axes (like horizontal or vertical). Using sine and cosine functions, we can pinpoint exactly how much of a force acts horizontally and how much vertically.
- **Practical Problem Solving**: Consider practical tasks like pulling a sled or pushing a shopping cart on a bumpy road. Trigonometry allows calculating how much effort goes towards actual movement versus how much is lost or used elsewhere.
- **Vectors and Angles**: In physics, forces are vectors and usually have directions, not just magnitudes. Trigonometry helps manage these directions by projecting forces on identifiable pathways (horizontal and vertical). This helps in both visualization and calculation steps.