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Fitzhugh-Nagumo equations Consider the followingalternative form of the Fitzhugh-Nagumo equations from Example \(3 :\) \(\frac{d v}{d t}=(v-a)(1-v) v-w \quad \frac{d w}{d t}=\varepsilon(v-w)\) where \(\varepsilon>0\) and \(0

Short Answer

Expert verified
Identify nullclines and equilibria, then plot them on a phase plane with directional arrows.

Step by step solution

01

Identify Nullclines

Nullclines are curves where the rate of change of variables is zero. For the Fitzhugh-Nagumo equations, we need to find where \(\frac{dv}{dt} = 0\) and \(\frac{dw}{dt} = 0\). Solve \((v-a)(1-v)v - w = 0\) for the \(v\)-nullcline and \(\varepsilon(v-w) = 0\) for the \(w\)-nullcline.
02

Solve for Nullclines

For the \(v\)-nullcline, solve \((v-a)(1-v)v = w\). This expresses \(w\) in terms of \(v\). For the \(w\)-nullcline, from \(\varepsilon(v-w) = 0\), we find \(w = v\). These lines will help plot where the system does not change along the \(v\) and \(w\) directions, respectively.
03

Find Equilibria

Equilibria occur where both the \(v\)-nullcline and \(w\)-nullcline intersect; thus, both equations \((v-a)(1-v)v = v\) (substitute \(w = v\)) must be satisfied. Solve this equation to find equilibrium points.
04

Plot Phase Plane

On the plane defined by axes \(v\) and \(w\), plot the nullclines obtained from previous steps. The \(w = v\) line is a straight line through the origin with a slope of 1. The \(v\)-nullcline should describe a cubic curve depending on \(a\). Mark the equilibria where both nullclines intersect.
05

Add Directional Arrows

Determine the direction of movement in different regions of the phase plane using the sign of the derivatives. Above the \(w\)-nullcline (\(w = v\)), \(\frac{dw}{dt} < 0\), and below it, \(\frac{dw}{dt} > 0\). Similarly, to the sides of the \(v\)-nullcline, analyze \(\frac{dv}{dt}\). Draw arrows indicating movement directions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phase Plane Analysis
A phase plane provides a visual way of understanding the dynamics of a system of differential equations. In the context of the FitzHugh-Nagumo equations, it allows us to explore how variables "v" and "w" interact over time.

The axes of the phase plane represent the variables: typically, "v" on one axis and "w" on the other. When plotting in this plane, we highlight important features such as nullclines and equilibrium points.
  • Nullclines indicate where the change in a variable is zero, helping define areas of stability.
  • Equilibrium points, where all changes are zero, can correspond to steady states of the system.
Phase plane analysis helps developers understand how systems evolve over time, determining behavior such as oscillations or steady state convergence. This visual tool is crucial for grasping complex dynamical systems like neural networks described by the FitzHugh-Nagumo model.
Nullclines
Nullclines are the foundation of phase plane analysis in dynamical systems. They are curves on a phase plane where the rate of change of one of the variables is zero.

In the FitzHugh-Nagumo equations:
  • The **v-nullcline** is found by solving \((v-a)(1-v)v = w\). This tells us where the derivative of "v" is zero, depending on "w".
  • The **w-nullcline** is given by \(w = v\). This is simply a line with slope 1, showing where the derivative of "w" is zero.
Intersections of nullclines in the phase plane identify points where neither variable changes. These overlapping positions are thus crucial, as they hint at potential equilibria.

By understanding these nullclines, you map out the system's potential dynamics and gather insights into stable or unstable areas.
Equilibrium Points
Equilibrium points in a dynamical system are where all changes cease, meaning both \(\frac{dv}{dt} = 0\) and \(\frac{dw}{dt} = 0\). At these points, the system can either remain steady or oscillate around them, depending on stability.

For the FitzHugh-Nagumo model, equilibrium points are the intersections of the nullclines \((v-a)(1-v)v = v\) and \(w = v\). Solving these equations simultaneously provides precise coordinates of equilibria in the phase plane.
  • Depending on the chosen parameters \(a\) and \(\varepsilon\), the number and nature of equilibrium points may vary.
  • These points are crucial in predicting the behavior of the system over time.
Stability analysis of these points involves examining the surrounding directional field, providing insights into whether the system will return to equilibrium or diverge away.
Directional Field
Directional fields illustrate the trajectory of a system in the phase plane by showing the direction of the vector field, determined by the differential equations.

In practice, you
  • Analyze regions around nullclines to determine the sign and behavior of \(\frac{dv}{dt}\) and \(\frac{dw}{dt}\).
  • Draw arrows indicating how solutions (trajectories) move in different regions of the phase plane.
For instance, in the FitzHugh-Nagumo equations:
  • Above the line \(w = v\), if \(\frac{dw}{dt} < 0\), the trajectories tend downward.
  • Below, when \(\frac{dw}{dt} > 0\), they tend upward.
The directional field visually communicates how variables interact and evolve, showing other possible paths the system may take. This empowers students to grasp a complete picture of the system's dynamical behavior.

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Most popular questions from this chapter

Metastasis of malignant tumors Metastasis is the process by which cancer cells spread throughout the body and initiate tumors in various organs. This sometimes happens via the bloodstream, where cancer cells become lodged in capillaries of organs and then move across the capillary wall into the organ. Using \(\mathrm{C}\) to denote the number of cells lodged in a capillary and \(I\) for the number that have invaded the organ, we can model this as \(C^{\prime}=-\alpha C-\beta C \quad I^{\prime}=\alpha C-\delta I+\rho I\) where all constants are positive, \(\alpha\) is the rate of movement across the capillary wall, \(\beta\) is the rate of dislodgment from the capillary, \(\delta\) is the rate at which cancer cells in the organ die, and \(\rho\) is their growth rate. (a) Suppose \(\rho<\delta .\) Construct the phase plane, including all nullclines, equilibria, and arrows indicating the direction of movement in the plane. (b) Suppose \(\rho<\delta .\) Construct the phase plane, including all nullclines, equilibria, and arrows indicating the direction of movement in the plane (c) What is the difference in the predicted dynamics between part (a) and part (b)?

Verify that \(y=-t \cos t-t\) is a solution of the initial-value problem $$t \frac{d y}{d t}=y+t^{2} \sin t \quad y(\pi)=0$$ Is this differential equation pure-time, autonomous, or nonautonomous?

Lung ventilation A patient is placed on a ventilator remove \(\mathrm{CO}_{2}\) from the lungs. Suppose that the rate of ventilation is \(100 \mathrm{mL} / \mathrm{s},\) with the percentage of \(\mathrm{CO}_{2}(\mathrm{by}\)volume) in the inflow being zero. Suppose also that air is absorbed by the lungs at a rate of 10 \(\mathrm{mL} / \mathrm{s}\) and gas consisting of 100\(\%\mathrm{CO}_{2}\) is excreted back into the lungs at the same rate. The volume of a typical pair of lungs is around 4000 \(\mathrm{mL} .\) If the patient starts ventilation with 20\(\%\) of lung volume being \(\mathrm{CO}_{2},\) what volume of \(\mathrm{CO}_{2}\) will remain in the lungs after 30 minutes?

A system of differential equations is given. (a) Use a phase plane analysis to determine the values of the constant \(a\) for which the sole equilibrium of the differential equations is locally stable. (b) Obtain an expression for each equilibrium (it may be a function of the constant \(a\) ). \(x^{\prime}=a(x-a), \quad y^{\prime}=4-y-x, \quad a \neq 0\)

Solve the differential equation \(x y ^ { \prime } = y + x e ^ { y / x }\) by making the change of variable \(v = y / x .\)

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