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Antibiotic pharmacokinetics Suppose that antibiotics are injected into a patient to treat a sinus infection. The antibiotics circulate in the blood, slowly diffusing into the sinus cavity while simultaneously being filtered out of the blood by the liver. In Chapter 10 we will derive a model for the concentration of the antibiotic in the sinus cavity as a function of time since the injection: $$ c(t)=\frac{e^{-\alpha t}-e^{-\beta t}}{\beta-\alpha} \quad \text { where } \beta>\alpha>0 $$ $$ \begin{array}{l}{\text { (a) At what time does } c \text { have its maximum value? }} \\ {\text { (b) At what time does the inflection point occur? What is }} \\ {\text { the significance of the inflection point for the concen- }} \\\ {\text { tration function? }} \\ {\text { (c) Sketch the graph of } c \text { . }}\end{array} $$

Short Answer

Expert verified
(a) Maximum at \( t = \frac{\log(\alpha) - \log(\beta)}{\beta - \alpha} \). (b) Inflection at \( t = \frac{2\log(\alpha) - 2\log(\beta)}{\beta - \alpha} \). (c) Sketch shows initial increase, peak, then decreases.

Step by step solution

01

Find the Derivative for Maximum Value

To find when the function has its maximum value, we first need to find the derivative of the concentration function, \( c(t) = \frac{e^{-\alpha t} - e^{-\beta t}}{\beta - \alpha} \). Using the rules of differentiation, the derivative is: \[ c'(t) = \frac{-\alpha e^{-\alpha t} + \beta e^{-\beta t}}{\beta - \alpha} \]
02

Set Derivative to Zero

Setting the derivative equal to zero will help us find the critical points. Thus, we set:\[ -\alpha e^{-\alpha t} + \beta e^{-\beta t} = 0 \]Solving for \( t \), we get:\[ \beta e^{-\beta t} = \alpha e^{-\alpha t} \]
03

Solve for t (Maximum Value)

Taking natural logarithms on both sides can help further simplify the equation from Step 2:\[ \log(\beta) - \beta t = \log(\alpha) - \alpha t \]Re-arranging and solving for \( t \) gives:\[ t = \frac{\log(\alpha) - \log(\beta)}{\beta - \alpha} \]
04

Find the Second Derivative for Inflection Point

The inflection point occurs when the second derivative of \( c(t) \) changes sign. First, find the second derivative:\[ c''(t) = \frac{\alpha^2 e^{-\alpha t} - \beta^2 e^{-\beta t}}{\beta - \alpha} \]
05

Set the Second Derivative to Zero

The second derivative should be equal to zero to find the point of inflection:\[ \alpha^2 e^{-\alpha t} = \beta^2 e^{-\beta t} \]Taking natural logarithm yields:\[ 2\log(\alpha) - \alpha t = 2\log(\beta) - \beta t \]
06

Solve for t (Inflection Point)

Solving the expression from Step 5, we can find:\[ t = \frac{2\log(\alpha) - 2\log(\beta)}{\beta - \alpha} \]
07

Significance of Inflection Point

The inflection point signifies when the rate of antibiotic concentration change is greatest. Before this point, the concentration increases at a decreasing rate, and after it, the increase at an increasing rate, until maximum.
08

Sketch the Graph of c(t)

The graph of \( c(t) \) is an increasing function that starts from zero, reaches a peak (maximum) at \( t = \frac{\log(\alpha) - \log(\beta)}{\beta - \alpha} \), and then decreases slowly approaching zero. The inflection point occurs at \( t = \frac{2\log(\alpha) - 2\log(\beta)}{\beta - \alpha} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are vital to many fields, including medicine, where they help us understand and predict how concentrations of drugs change over time. In the problem at hand, we explore the dynamics of antibiotic concentration in the blood and sinus cavities after they have been injected into a patient. This is expressed using a differential equation in the form of a concentration function:\[ c(t) = \frac{e^{-\alpha t} - e^{-\beta t}}{\beta - \alpha} \]We use differential equations here to find out when the function reaches its peak, or maximum concentration. This is done by taking the derivative of the concentration function \( c(t) \) and finding where this derivative equals zero. Here's why this is important:
  • Describing Changes: Differential equations describe the rate of change of a quantity, which can be a very slight change, as in this case, where drugs slowly filter out of the bloodstream.
  • Finding Critical Points: By setting the derivative to zero, we identify critical points where the rate of change is zero, indicating a possible maximum (as in step 3 of the solution).
The derivative equation, \( c'(t) = \frac{-\alpha e^{-\alpha t} + \beta e^{-\beta t}}{\beta - \alpha} \), helps us find these critical points by solving \( \beta e^{-\beta t} = \alpha e^{-\alpha t} \), leading to our understanding of how and when the antibiotic reaches its peak effectiveness.
Calculus in Medicine
Calculus, especially techniques involving differentiation and integration, plays a crucial role in pharmacokinetics—the branch of pharmacology dedicated to determining the fate of substances administered to a living organism. It enables us to calculate key aspects like the peak concentration time and the period of most rapid change in concentration of a drug.Calculus allows us to not only identify the maximum concentration of the antibiotic but also the inflection points using second derivatives. The second derivative, \( c''(t) = \frac{\alpha^2 e^{-\alpha t} - \beta^2 e^{-\beta t}}{\beta - \alpha} \), provides information about the curvature of the concentration function.
  • Inflection Points: These are points where the curve changes its concavity, marking the transition in how fast the concentration is increasing or decreasing.
  • Practical Implications: Understanding when inflection points occur, such as \( t = \frac{2\log(\alpha) - 2\log(\beta)}{\beta - \alpha} \), can inform medical professionals about when the drug exhibits the most significant rate change, which is essential for treatment planning.
Thus, calculus is not just about solving mathematical problems but directly applying these solutions to enhance patient care and treatment strategies.
Mathematical Modeling
Mathematical modeling is a powerful tool used to simulate complex real-world scenarios, like the behavior of a drug within a patient's system. Through mathematical models, we represent and solve the behavior of physiological processes analytically.In this exercise, our model is represented by the function:\[ c(t) = \frac{e^{-\alpha t} - e^{-\beta t}}{\beta - \alpha} \]This function provides a model for the concentration level of an antibiotic in a sinus cavity as time progresses following the injection.
  • Predictive Power: Models allow predictions about how concentrations change with time, which can be critical for devising dosing schedules.
  • Understanding Parameters:The parameters \( \alpha \) and \( \beta \) uniquely determine how fast the drug is processed and filtered by the body, influencing the shape and behavior of the concentration curve.
  • Visual Representation: By plotting this function (as suggested in the step-by-step solution), we can visualize how the drug concentration evolves, observing where it peaks and how it declines—a direct implication of the model's predictions.
Mathematical modeling thus provides a bridge between abstract calculations and tangible clinical insights, enriching our understanding of pharmacokinetics and optimizing therapeutic interventions.

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