Chapter 4: Problem 41
Rank the functions in order of how quickly they grow as \(x \rightarrow \infty\). \(y=(\ln x)^{2}, \quad y=(\ln x)^{3}, \quad y=\sqrt{x}, \quad y=\sqrt[3]{x}\)
Short Answer
Expert verified
\( y = \\sqrt{x} > y = \\sqrt[3]{x} > y = (\ln x)^3 > y = (\ln x)^2 \).
Step by step solution
01
Analyze Polynomial Growth
Consider the function \( y = x^n \). If a function is a polynomial like \( y = \sqrt{x} = x^{1/2} \) or \( y = \sqrt[3]{x} = x^{1/3} \), we compare their powers. Here, \( y = x^{1/2} \) grows faster than \( y = x^{1/3} \) because \( 1/2 > 1/3 \).
02
Analyze Logarithmic Growth
Consider logarithmic functions such as \( y = (\ln x)^2 \) and \( y = (\ln x)^3 \). Since \( (\ln x)^3 \) contains a higher power of the logarithmic term than \( (\ln x)^2 \), \( y = (\ln x)^3 \) grows faster than \( y = (\ln x)^2 \) as \( x \rightarrow \infty \).
03
Compare Polynomial and Logarithmic Growth
Polynomial functions like powers of \( x \) (e.g., \( y = \sqrt{x} \)) generally grow faster than logarithmic functions raised to a power (e.g., \( y = (\ln x)^2 \) or \( y = (\ln x)^3 \)) as \( x \rightarrow \infty \). Hence, \( y = \sqrt{x} \) and \( y = \sqrt[3]{x} \) both grow faster than \( y = (\ln x)^2 \) and \( y = (\ln x)^3 \).
04
Rank the Functions
Combine the insights: the fastest-growing function is \( y = \sqrt{x} \), followed by \( y = \sqrt[3]{x} \), then \( y = (\ln x)^3 \), and the slowest-growing is \( y = (\ln x)^2 \). The rank order is: \( y = \sqrt{x} > y = \sqrt[3]{x} > y = (\ln x)^3 > y = (\ln x)^2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Functions
Polynomial functions are essential building blocks in mathematics. They are expressions involving a variable raised to a power, such as \( y = x^n \). The term "power" here refers to the exponent \( n \), which can be any real number. Polynomials can have various characteristics influencing their growth:
- The higher the exponent, the faster the polynomial grows as \( x \) approaches infinity. For instance, comparing \( y = x^{1/2} \) and \( y = x^{1/3} \), the former grows faster because 1/2 is greater than 1/3.
- Polynomial functions have a straightforward asymptotic behavior, as they steadily increase without bound when the exponent is positive.
Logarithmic Functions
Logarithmic functions involve exponents and growth differently than polynomials. A basic example is the natural logarithm, denoted as \( \ln x \). When raised to a power, as in \( y = (\ln x)^n \), they reflect slow growth patterns:
- Higher powers of logarithmic functions, such as \( (\ln x)^3 \) versus \( (\ln x)^2 \), still grow more slowly than comparable polynomial functions with fractional powers.
- Logarithms grow by increasing small incremental values. For example, transitioning from \( \ln 10 \) to \( \ln 100 \) represents a small growth step in a logarithm's entire range.
Asymptotic Behavior
Asymptotic behavior provides insight into how functions grow relative to each other as \( x \) approaches infinity. It helps identify which functions grow faster as they extend towards larger values of \( x \). Here are some key points:
- Polynomials typically display straightforward asymptotic behavior due to their constant faster growth, especially compared to logarithmic functions.
- Logarithmic functions grow even more slowly, showing only slight increases even as \( x \) becomes very large.
- In asymptotic terms, the ranking of the growth rates for our original set of functions was derived: \( y = \sqrt{x} \) grows fastest, followed by \( y = \sqrt[3]{x} \), then \( y = (\ln x)^3 \), and lastly, \( y = (\ln x)^2 \).