Chapter 4: Problem 16
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why. \(\lim _{x \rightarrow 0} \frac{\cos m x-\cos n x}{x^{2}}\)
Short Answer
Expert verified
Limit is \(\frac{n^2 - m^2}{2}\).
Step by step solution
01
Verify Indeterminate Form
First, evaluate the limit's form by substituting \(x = 0\) into the expression. This will help us determine if l'Hospital's Rule can be applied.Substitute \(x = 0\):\[\frac{\cos(mx) - \cos(nx)}{x^2} = \frac{\cos(0) - \cos(0)}{0^2} = \frac{1 - 1}{0} = \frac{0}{0}\].This is an indeterminate form \(\frac{0}{0}\), so we can proceed with l'Hospital's Rule.
02
Apply l'Hospital's Rule
Since we have the indeterminate form \(\frac{0}{0}\), we can apply l'Hospital's Rule, which involves differentiating the numerator and the denominator.The derivative of the numerator \( \cos(mx) - \cos(nx) \) is:\[-m \sin(mx) + n \sin(nx)\].The derivative of the denominator \(x^2\) is \(2x\).
03
Evaluate the New Limit
Substitute these derivatives into the limit:\[\lim_{x \to 0} \frac{-m \sin(mx) + n \sin(nx)}{2x}\].Again substitute \(x = 0\) to check for an indeterminate form:\[\frac{-m \sin(0) + n \sin(0)}{2(0)} = \frac{0}{0}\].The new limit remains an indeterminate form, so apply l'Hospital's Rule again.
04
Apply l'Hospital's Rule Again
Differentiate the numerator and denominator a second time.The second derivative of the numerator is:\[-m^2 \cos(mx) + n^2 \cos(nx)\].The second derivative of the denominator is \(2\).
05
Evaluate the Limit Again
Now the limit is simplified to:\[\lim_{x \to 0} \frac{-m^2 \cos(mx) + n^2 \cos(nx)}{2}\].Now substitute \(x = 0\):\[\frac{-m^2 \cos(0) + n^2 \cos(0)}{2} = \frac{-m^2(1) + n^2(1)}{2} = \frac{-m^2 + n^2}{2}\].This yields a finite value and is the solution.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits in Calculus
Limits are a fundamental concept in calculus, serving as the foundation for derivatives and integrals. A limit describes the value that a function approaches as the input approaches a certain point. Understanding limits is crucial, especially when dealing with functions that behave unpredictably near certain values.
In the exercise, we aim to find the limit as \(x\) approaches 0 for the expression \(\frac{\cos mx - \cos nx}{x^2}\). This requires analyzing how the expression behaves near \(x = 0\).
In the exercise, we aim to find the limit as \(x\) approaches 0 for the expression \(\frac{\cos mx - \cos nx}{x^2}\). This requires analyzing how the expression behaves near \(x = 0\).
- Always substitute the limit value into the function first to determine its form.
- A limit helps us understand behaviors and solve problems involving instantaneous rates of change.
- Being able to rigorously evaluate a limit ensures a strong understanding of functionality within calculus.
l'Hopital's Rule
l'Hopital's Rule is a powerful tool for finding limits of functions that result in indeterminate forms. This rule states that if the limit of a fraction yields an indeterminate form like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), then the limit of the derivatives of the numerator and denominator can be taken instead.
For the given exercise, after confirming the form \(\frac{0}{0}\), we can apply l'Hopital's Rule. This involves taking the derivatives of both the numerator \(\cos mx - \cos nx\) and the denominator \(x^2\). By simplifying the function in terms of its derivatives, we systematically find the limit.
For the given exercise, after confirming the form \(\frac{0}{0}\), we can apply l'Hopital's Rule. This involves taking the derivatives of both the numerator \(\cos mx - \cos nx\) and the denominator \(x^2\). By simplifying the function in terms of its derivatives, we systematically find the limit.
- An essential precondition is confirming the indeterminate form by initial substitution.
- After differentiation, evaluate the new limit to see if further application of l'Hopital's Rule is necessary.
- l'Hopital's Rule simplifies complex limits, making subtle approaches more straightforward.
Indeterminate Forms
Indeterminate forms are expressions that do not initially provide enough information to determine a specific limit. Common indeterminate forms include \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), and others like \(0 \cdot \infty\). They occur frequently in calculus, especially when evaluating limits.
In the example provided, substituting \(x = 0\) results in the indeterminate form \(\frac{0}{0}\). This signals a need to use a method, such as l'Hopital's Rule, to find the actual limit value.
In the example provided, substituting \(x = 0\) results in the indeterminate form \(\frac{0}{0}\). This signals a need to use a method, such as l'Hopital's Rule, to find the actual limit value.
- Not all indeterminate forms can be simplified directly; some may need transformations or entirely different approaches.
- Recognizing an indeterminate form is the first crucial step in applying further calculus methods like l'Hopital's Rule.
- Identifying these forms helps in deploying the correct mathematical tools effectively.
Derivative Calculations
Derivative calculations form the backbone of calculus, providing the means to compute the rate at which a quantity changes. Understanding derivatives is essential to apply l'Hopital's Rule and resolve indeterminate forms.
For this problem, after confirming the indeterminate form \(\frac{0}{0}\), the derivative of the function's parts must be calculated. The derivatives of the trigonometric components \(\cos(mx) - \cos(nx)\) result in \(-m \sin(mx) + n \sin(nx)\), while the derivative of \(x^2\) gives us \(2x\).
For this problem, after confirming the indeterminate form \(\frac{0}{0}\), the derivative of the function's parts must be calculated. The derivatives of the trigonometric components \(\cos(mx) - \cos(nx)\) result in \(-m \sin(mx) + n \sin(nx)\), while the derivative of \(x^2\) gives us \(2x\).
- Calculating derivatives systematically clarifies the behavior of functions, especially at critical points.
- In sequences of problems involving limits, calculating derivatives is often repeated, reinforcing knowledge and practice.
- The accuracy of derivatives directly impacts the validity of the results obtained through l'Hopital's Rule.