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Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why. \(\lim _{x \rightarrow 0} \frac{\cos m x-\cos n x}{x^{2}}\)

Short Answer

Expert verified
Limit is \(\frac{n^2 - m^2}{2}\).

Step by step solution

01

Verify Indeterminate Form

First, evaluate the limit's form by substituting \(x = 0\) into the expression. This will help us determine if l'Hospital's Rule can be applied.Substitute \(x = 0\):\[\frac{\cos(mx) - \cos(nx)}{x^2} = \frac{\cos(0) - \cos(0)}{0^2} = \frac{1 - 1}{0} = \frac{0}{0}\].This is an indeterminate form \(\frac{0}{0}\), so we can proceed with l'Hospital's Rule.
02

Apply l'Hospital's Rule

Since we have the indeterminate form \(\frac{0}{0}\), we can apply l'Hospital's Rule, which involves differentiating the numerator and the denominator.The derivative of the numerator \( \cos(mx) - \cos(nx) \) is:\[-m \sin(mx) + n \sin(nx)\].The derivative of the denominator \(x^2\) is \(2x\).
03

Evaluate the New Limit

Substitute these derivatives into the limit:\[\lim_{x \to 0} \frac{-m \sin(mx) + n \sin(nx)}{2x}\].Again substitute \(x = 0\) to check for an indeterminate form:\[\frac{-m \sin(0) + n \sin(0)}{2(0)} = \frac{0}{0}\].The new limit remains an indeterminate form, so apply l'Hospital's Rule again.
04

Apply l'Hospital's Rule Again

Differentiate the numerator and denominator a second time.The second derivative of the numerator is:\[-m^2 \cos(mx) + n^2 \cos(nx)\].The second derivative of the denominator is \(2\).
05

Evaluate the Limit Again

Now the limit is simplified to:\[\lim_{x \to 0} \frac{-m^2 \cos(mx) + n^2 \cos(nx)}{2}\].Now substitute \(x = 0\):\[\frac{-m^2 \cos(0) + n^2 \cos(0)}{2} = \frac{-m^2(1) + n^2(1)}{2} = \frac{-m^2 + n^2}{2}\].This yields a finite value and is the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits in Calculus
Limits are a fundamental concept in calculus, serving as the foundation for derivatives and integrals. A limit describes the value that a function approaches as the input approaches a certain point. Understanding limits is crucial, especially when dealing with functions that behave unpredictably near certain values.

In the exercise, we aim to find the limit as \(x\) approaches 0 for the expression \(\frac{\cos mx - \cos nx}{x^2}\). This requires analyzing how the expression behaves near \(x = 0\).
  • Always substitute the limit value into the function first to determine its form.
  • A limit helps us understand behaviors and solve problems involving instantaneous rates of change.
  • Being able to rigorously evaluate a limit ensures a strong understanding of functionality within calculus.
Remember, limits provide a way to "peek" at the behavior of functions near specific points without necessarily evaluating them directly at those points.
l'Hopital's Rule
l'Hopital's Rule is a powerful tool for finding limits of functions that result in indeterminate forms. This rule states that if the limit of a fraction yields an indeterminate form like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), then the limit of the derivatives of the numerator and denominator can be taken instead.

For the given exercise, after confirming the form \(\frac{0}{0}\), we can apply l'Hopital's Rule. This involves taking the derivatives of both the numerator \(\cos mx - \cos nx\) and the denominator \(x^2\). By simplifying the function in terms of its derivatives, we systematically find the limit.
  • An essential precondition is confirming the indeterminate form by initial substitution.
  • After differentiation, evaluate the new limit to see if further application of l'Hopital's Rule is necessary.
  • l'Hopital's Rule simplifies complex limits, making subtle approaches more straightforward.
It gives us an effective way to deal with limits too complicated for simple algebraic manipulation.
Indeterminate Forms
Indeterminate forms are expressions that do not initially provide enough information to determine a specific limit. Common indeterminate forms include \(\frac{0}{0}\), \(\frac{\infty}{\infty}\), and others like \(0 \cdot \infty\). They occur frequently in calculus, especially when evaluating limits.

In the example provided, substituting \(x = 0\) results in the indeterminate form \(\frac{0}{0}\). This signals a need to use a method, such as l'Hopital's Rule, to find the actual limit value.
  • Not all indeterminate forms can be simplified directly; some may need transformations or entirely different approaches.
  • Recognizing an indeterminate form is the first crucial step in applying further calculus methods like l'Hopital's Rule.
  • Identifying these forms helps in deploying the correct mathematical tools effectively.
Having a deep understanding of indeterminate forms prepares you for the nuanced calculations often required in calculus.
Derivative Calculations
Derivative calculations form the backbone of calculus, providing the means to compute the rate at which a quantity changes. Understanding derivatives is essential to apply l'Hopital's Rule and resolve indeterminate forms.

For this problem, after confirming the indeterminate form \(\frac{0}{0}\), the derivative of the function's parts must be calculated. The derivatives of the trigonometric components \(\cos(mx) - \cos(nx)\) result in \(-m \sin(mx) + n \sin(nx)\), while the derivative of \(x^2\) gives us \(2x\).
  • Calculating derivatives systematically clarifies the behavior of functions, especially at critical points.
  • In sequences of problems involving limits, calculating derivatives is often repeated, reinforcing knowledge and practice.
  • The accuracy of derivatives directly impacts the validity of the results obtained through l'Hopital's Rule.
Mastering these calculations ensures precision, allowing you to solve complex calculus problems with confidence.

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