Chapter 3: Problem 7
Differentiate the function. $$f(x)=\sqrt[5]{\ln x}$$
Short Answer
Expert verified
The derivative is \( f'(x) = \frac{1}{5x} (\ln x)^{-4/5} \).
Step by step solution
01
Rewrite the Function
Rewrite the function in a form that's easier to differentiate. The given function is \( f(x) = \sqrt[5]{\ln x} \). We can rewrite this as \( f(x) = (\ln x)^{1/5} \).
02
Apply the Power Rule
The power rule for differentiation says if \( f(x) = u^n \), then \( f'(x) = n \, u^{n-1} \, u' \). Here, \( u = \ln x \) and \( n = \frac{1}{5} \).
03
Differentiate \( u = \ln x \)
Find the derivative of \( u = \ln x \). The derivative \( u' \) is \( \frac{1}{x} \).
04
Apply the Chain Rule
Using the chain rule, we differentiate \( f(x) = (\ln x)^{1/5} \) and get: \[ f'(x) = \frac{1}{5} (\ln x)^{-4/5} \times \frac{1}{x} \].
05
Simplify the Expression
Combine and simplify the expression for the derivative: \[ f'(x) = \frac{1}{5x} (\ln x)^{-4/5} \]. This is the simplified form of the derivative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule in Calculus
The Power Rule is a fundamental tool in calculus for differentiation. It's used when you have a function in the form of a power, like \( f(x) = x^n \). The rule states that the derivative of \( x^n \) is \( nx^{n-1} \). In simpler terms, you multiply by the power, then subtract one from the power.
To illustrate, if you have a function \( y = x^3 \), applying the Power Rule gives you \( y' = 3x^{2} \). This makes finding the rate of change quick and efficient.
To illustrate, if you have a function \( y = x^3 \), applying the Power Rule gives you \( y' = 3x^{2} \). This makes finding the rate of change quick and efficient.
- Identify the power of the expression.
- Multiply by the exponent.
- Subtract one from the exponent.
Chain Rule
The Chain Rule is used when differentiating a "function of a function," meaning one that involves a combination of two functions. If you see something like \( f(x) = g(h(x)) \), the Chain Rule helps break it down. It's expressed as \( f'(x) = g'(h(x)) \cdot h'(x) \). So, you differentiate the outer function first and then multiply by the derivative of the inner function.
An example would be if \( f(x) = (2x+3)^2 \), you'd differentiate the outer function \((u^2)\) to get \( 2u \), and then the inner function \((2x+3) \to 2 \), resulting in \( 4(2x+3) \).
An example would be if \( f(x) = (2x+3)^2 \), you'd differentiate the outer function \((u^2)\) to get \( 2u \), and then the inner function \((2x+3) \to 2 \), resulting in \( 4(2x+3) \).
- Identify the outer and inner functions.
- Dfferentiate the outer function, leaving the inner function intact.
- Multiply by the derivative of the inner function.
Natural Logarithm Differentiation
Differentiation of logarithmic functions, specifically the natural log, which is denoted as \( \ln(x) \), follows a straightforward rule. The derivative of \( \ln(x) \) is \( \frac{1}{x} \). This makes logarithmic differentiation particularly useful as it simplifies complex algebraic expressions, breaking them down into manageable parts.
For example, if your function is \( y = \ln(x) \), its derivative directly becomes \( y' = \frac{1}{x} \). Another practical application is when you have a logarithm raised to a power or multiplied within another function.
For example, if your function is \( y = \ln(x) \), its derivative directly becomes \( y' = \frac{1}{x} \). Another practical application is when you have a logarithm raised to a power or multiplied within another function.
- Notice how the derivative converts a logarithm into a reciprocal.
- Use it in combination with other differentiation rules like the Chain Rule.