Chapter 3: Problem 32
32\. Let$$f(x)=\log _{b}\left(3 x^{2}-2\right) . \text { For what value of } b \text { is } f^{\prime}(1)=3 ?$$
Short Answer
Expert verified
The value of \( b \) is \( e^2 \).
Step by step solution
01
Understanding the Function and Derivative
The function given is \( f(x) = \log_b(3x^2 - 2) \). We are required to find the value of \( b \) such that the derivative \( f'(1) = 3 \).
02
Apply the Derivative Formula
The derivative of \( f(x) = \log_b(u) \) with respect to \( x \) is \( f'(x) = \frac{1}{u \ln(b)} \cdot u' \) where \( u = 3x^2 - 2 \) and \( u' \) is its derivative.
03
Find the Derivative of the Inner Function
Differentiate the inner function \( 3x^2 - 2 \). The derivative is \( u' = 6x \).
04
Calculate the Derivative of the Original Function
Substitute \( u = 3x^2 - 2 \) and \( u' = 6x \) into the formula: \[ f'(x) = \frac{6x}{(3x^2 - 2) \ln(b)} \].
05
Set up the Equation for \( f'(1) = 3 \)
Substitute \( x = 1 \) into the derivative expression: \[ f'(1) = \frac{6 \times 1}{(3 \times 1^2 - 2)\ln(b)} = 3 \].
06
Solve for \( b \)
Simplify the equation: \[ \frac{6}{1 \ln(b)} = 3 \]. This reduces to \[ 6 = 3 \ln(b) \], or \[ \ln(b) = 2 \].
07
Exponentiate to Find \( b \)
Exponentiate both sides to solve for \( b \): \[ b = e^2 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative of Logarithmic Function
When we talk about the derivative of a logarithmic function, it's essential to understand the basic formula first. If you have a function of the form \( f(x) = \log_b(u) \), where \( u \) is some function of \( x \), the derivative takes a specific form. Instead of working directly with the function, we'll focus on its rate of change.
This rate of change is known as the derivative. For a logarithmic function, the derivative \( f'(x) \) is expressed as:
This rate of change is known as the derivative. For a logarithmic function, the derivative \( f'(x) \) is expressed as:
- \( f'(x) = \frac{1}{u \ln(b)} \cdot u' \)
Chain Rule in Calculus
The chain rule is a core principle in calculus that lets us find the derivative of composite functions. It's like peeling layers of an onion; you deal with the outer layer before the inner one. If a function is composed of two or more functions intertwined, the chain rule guides us through the differentiation process.
Take a composite function \( f(x) = \log_b(3x^2 - 2) \). The outer function here is the logarithm \( \log_b \) and the inner function is \( 3x^2 - 2 \). To differentiate, we:
Take a composite function \( f(x) = \log_b(3x^2 - 2) \). The outer function here is the logarithm \( \log_b \) and the inner function is \( 3x^2 - 2 \). To differentiate, we:
- First, differentiate the outer function while keeping the inner function unchanged.
- Then, multiply by the derivative of the inner function (in our case, the derivative of \( 3x^2 - 2 \), which is \( 6x \)).
Calculus Problem-Solving Steps
Solving calculus problems is often a structured process. This means following clear steps to reach a solution. Let's look at a framework we can use:
- **Understand the problem:** Start by carefully reading what's being asked. Here, we need \( f'(1) = 3 \) for a specific function.
- **Break down the function:** Identify individual function parts and expressions, such as inner and outer functions.
- **Apply relevant calculus rules:** Use rules like the chain rule to differentiate effectively.
- **Substitute values:** Plug in numbers, such as \( x = 1 \), to simplify expressions where needed.
- **Solve for unknowns:** Here, it means manipulating the equation to solve for \( b \).
- **Verify your solution:** Always double-check calculations to ensure the answer makes logical sense.