Chapter 2: Problem 16
Determine whether the sequence is convergent or divergent. If it is convergent, find the limit. \(a_{n}=2^{-n}+6^{-n}\)
Short Answer
Expert verified
The sequence is convergent with a limit of 0.
Step by step solution
01
Identify the Sequence
The given sequence is \(a_n = 2^{-n} + 6^{-n}\). This sequence is expressed in terms of powers with a negative exponent, which means both terms \(2^{-n}\) and \(6^{-n}\) tend towards zero as \(n\) approaches infinity.
02
Analyze Each Term Separately
Consider the first term \(2^{-n}\). As \(n\) approaches infinity, the expression \(2^{-n}\) becomes smaller and converges to 0. Similarly, consider \(6^{-n}\). As \(n\) approaches infinity, the expression \(6^{-n}\) also becomes smaller and converges to 0.
03
Combine the Limits
Since both \(2^{-n}\) and \(6^{-n}\) individually converge to 0, their sum \(2^{-n} + 6^{-n}\) will also converge to \(0 + 0 = 0\).
04
Conclusion about Convergence
Since the sum of two converging sequences is itself convergent, \(a_n = 2^{-n} + 6^{-n}\) is a convergent sequence. The limit of the sequence as \(n\) approaches infinity is 0.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limit of a Sequence
In mathematics, the limit of a sequence refers to the value that the terms of a sequence approach as the index goes to infinity. When dealing with sequences, a sequence \(a_n\) is said to converge to a limit \(L\) if, as \(n\) becomes very large, the terms of the sequence get arbitrarily close to \(L\). This concept is crucial in calculus and analysis, providing a foundation for understanding more complex mathematical ideas.
To determine the limit of a sequence, you observe how the terms behave when the index becomes very large. If they settle towards a single, finite value, this value is the limit of the sequence. For example, if we examine \(2^{-n}\), as \(n\) approaches infinity, \(2^{-n} \) gets smaller and smaller, specifically, it approaches 0. Thus, the limit of \(2^{-n}\) as \(n\) goes to infinity is 0.
Ultimately, understanding the limit helps to predict the behavior of sequences, which is useful for solving real-world problems in engineering, computer science, and physics.
To determine the limit of a sequence, you observe how the terms behave when the index becomes very large. If they settle towards a single, finite value, this value is the limit of the sequence. For example, if we examine \(2^{-n}\), as \(n\) approaches infinity, \(2^{-n} \) gets smaller and smaller, specifically, it approaches 0. Thus, the limit of \(2^{-n}\) as \(n\) goes to infinity is 0.
Ultimately, understanding the limit helps to predict the behavior of sequences, which is useful for solving real-world problems in engineering, computer science, and physics.
Convergence and Divergence
The concepts of convergence and divergence are pivotal when analyzing sequences and series. A sequence is said to be convergent if its terms tend to approach a particular value as the sequence progresses. Conversely, a sequence is divergent if its terms do not approach any particular value as the sequence progresses without bound.
Understanding whether sequences converge or diverge is not just an academic exercise; it plays a crucial role in defining and working with infinite series and ensuring stability in numerical methods.
- **Convergent Sequence:** Here, \(a_n = 2^{-n} + 6^{-n}\) is a great example. Both terms, \(2^{-n}\) and \(6^{-n}\), individually converge to 0. When combined, their sum \(2^{-n} + 6^{-n}\) converges to 0 as well, demonstrating convergent behavior.
- **Divergent Sequence:** In other instances where terms do not settle down to a single value, the sequence is divergent. For instance, simple sequences like \(a_n = n\) are divergent because they head off to infinity as \(n\) increases.
Understanding whether sequences converge or diverge is not just an academic exercise; it plays a crucial role in defining and working with infinite series and ensuring stability in numerical methods.
Negative Exponents
Negative exponents represent the reciprocal of a number raised to a positive exponent. When you encounter a negative exponent, think of it as flipping the base number to the denominator position in a fraction. For example, \(2^{-n}\) is equivalent to \(\frac{1}{2^n}\).
The presence of negative exponents in sequences, like our example \(a_n = 2^{-n} + 6^{-n}\), fundamentally means that as \(n\) increases, each term of the sequence becomes smaller and smaller, trending towards zero. This behavior happens because \(2^{-n}\) and \(6^{-n}\) are essentially fractions with very large denominators as \(n\) increases.
The presence of negative exponents in sequences, like our example \(a_n = 2^{-n} + 6^{-n}\), fundamentally means that as \(n\) increases, each term of the sequence becomes smaller and smaller, trending towards zero. This behavior happens because \(2^{-n}\) and \(6^{-n}\) are essentially fractions with very large denominators as \(n\) increases.
- **Key Properties:**
- As \(n\) becomes larger, the value of \(2^{-n}\) and \(6^{-n}\) approaches zero, leading these terms to contribute increasingly less to the sum.
- Negative exponents often yield convergent behavior in sequences, especially when dealing with sums of multiple terms each tending towards zero.