Chapter 1: Problem 47
Find the domain and sketch the graph of the function. \(G(x)=\frac{3 x+|x|}{x}\)
Short Answer
Expert verified
Domain: All real numbers except 0. For \(x > 0\), \(G(x) = 4\), and for \(x < 0\), \(G(x) = 2\).
Step by step solution
01
Identify Function Constraints
To find the domain of the function, look at the elements that could make the function undefined. Here, the function has a denominator of \(x\). The function becomes undefined when \(x = 0\). Hence, \(xeq0\). The domain is all real numbers except 0.
02
Simplify the Function
Notice that the numerator is \(3x + |x|\). We have two cases based on the value of \(x\):- When \(x \geq 0\), then \(|x|=x\), and \(G(x)=\frac{3x+x}{x}=\frac{4x}{x}=4\).- When \(x < 0\), then \(|x|=-x\), and \(G(x)=\frac{3x-x}{x}=\frac{2x}{x}=2\).Hence, the function simplification gives us two pieces: \(G(x) = 4\) for \(x > 0\) and \(G(x) = 2\) for \(x < 0\).
03
Determine Function Behavior
Since we simplified the function: - For \(x > 0\), the function value is constant at 4.- For \(x < 0\), the function value is constant at 2.There is a discontinuity at \(x = 0\) because \(G(x)\) is not defined there.
04
Sketch the Graph
Plot the graph based on the piece-wised function:- For \(x > 0\), plot a horizontal line at \(y = 4\), starting right after 0 and extending to the right.- For \(x < 0\), plot a horizontal line at \(y = 2\), extending to the left.- Leave an open circle at \(x = 0\) because \(G(x)\) is undefined at that point.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a function
In mathematics, the domain of a function is the set of all possible input values (or x-values) that allow the function to work properly without any errors. For the function given, \[G(x)=\frac{3x+|x|}{x}\]we need to look out for conditions where the function becomes undefined. A common issue arises when the denominator of a fraction is zero. In this case, when \(x = 0\), the function is undefined because division by zero isn't possible.Therefore, the domain of this function is all real numbers except zero. We can express the domain with a set notation as:
- \( \{ x \in \mathbb{R} \mid x eq 0 \} \)
Absolute value function
The absolute value function, noted as \(|x|\), measures the distance of a number from zero on the number line. It always gives a non-negative result, regardless of whether the input is positive or negative.For our function, \[3x + |x|\]the absolute value influences the piecewise behavior:
- When \(x \geq 0\), the absolute value behaves normally, and \(|x| = x\).
- When \(x < 0\), the absolute value acts to negate the input, giving \(|x| = -x\).
- For \(x \geq 0\), \(G(x)\) simplifies to 4.
- For \(x < 0\), \(G(x)\) simplifies to 2.
Undefined points in a function
When approaching functions, it's crucial to identify any points where the function is not defined. In our function,\[G(x)=\frac{3x+|x|}{x}\]the function is undefined at \(x = 0\) due to division by zero.These undefined points mark gaps or interruptions in the overall function. To address undefined points:
- Identify the factors in the denominator.
- Check when these factors equal zero.
- Exclude these values from the domain to avoid errors.
Graph discontinuity
Graph discontinuity occurs when there are breaks or jumps in the graph of a function. For our piecewise function:
- For \(x > 0\), \(G(x)\) is a constant line at 4.
- For \(x < 0\), \(G(x)\) is a constant line at 2.