/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Simplify the expression. \(\le... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the expression. \(\left(\frac{9}{49}\right)^{1 / 2}\)

Short Answer

Expert verified
The simplified expression for \(\left(\frac{9}{49}\right)^{1 / 2}\) is \(3 / 7\).

Step by step solution

01

Recall power rule

Raise each part of the fraction (numerator and denominator) to the power of 1/2. This is equivalent to taking the square root of each part.
02

Simplify numerator

The numerator is 9. So, \((9)^{1/2}= 3\).
03

Simplify denominator

The denominator is 49. So, \((49)^{1/2}= 7\).
04

Final simplification

Now put the simplified numerator and denominator back together as a fraction, yielding \(3 / 7\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule
Understanding the power rule is crucial when simplifying expressions that involve exponents. The power rule states that when you raise a power to another power, you multiply the exponents. However, when you raise a base to a fractional power, it is equivalent to taking the root of the base.

For example, if you have a fraction raised to the power of 1/2, it means taking the square root of both the numerator and the denominator. In our original exercise, the expression \[\left(\frac{9}{49}\right)^{1/2}\]indicates that each part of the fraction—both the numerator and the denominator—should be individually raised to the 1/2 power, or in other words, each should be square rooted. This understanding simplifies the process significantly and is a fundamental technique when handling fractional exponents.

Remember that the power rule is applicable beyond just taking square roots; it's a versatile tool that helps simplify many algebraic expressions by appropriately managing exponents.
Square Roots
Square roots simplify expressions by finding the number which, when multiplied by itself, gives the original number. It is often denoted by the exponent 1/2 in mathematical operations.

In our case, the expression is \[\left(\frac{9}{49}\right)^{1/2}\].

This operation requires you to take the square root of 9 and 49 separately. The square root of 9 is 3 because 3 multiplied by itself (3 x 3) yields 9. Similarly, the square root of 49 is 7 since 7 times 7 equals 49.

Finding the square root is a special case of exponents, where numbers are expressed as the base raised to the power of 1/2. This provides a consistent approach to simplifying expressions that resemble fractional powers in algebra. By breaking down each part of the fraction and addressing them individually, it becomes much easier to arrive at the simplified form, which here turns out to be 3/7.
Numerator and Denominator Simplification
When simplifying fractions involving exponents, the task often involves breaking down the number at both the numerator and the denominator levels. In this step-by-step simplification, the primary aim is to transform complex expressions into simpler forms.

Let's take the fraction \[\left(\frac{9}{49}\right)^{1/2}\] as an example. The first operation involves isolating the numerator (9) and the denominator (49) and then simplifying them separately by taking their square roots.

The numerator, 9, becomes 3 because \[9^{1/2} = 3\]. Similarly, the denominator, 49, turns into 7 since \[49^{1/2} = 7\].
  • Simplify each part separately: take the root of each.
  • Apply the results back to form the reduced fraction.
Once both the numerator and the denominator have been simplified, the expression should be recomposed as a fraction. This gives us the outcome: \[\frac{3}{7}\], a much simpler representation. This method is essential for efficiently handling fraction simplification with ease.

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Most popular questions from this chapter

Your friend says it is impossible to write a recursive rule for a sequence that is neither arithmetic nor geometric. Is your friend correct? Justify your answer.

You sprain your ankle and your doctor prescribes 325 milligrams of an anti- infl ammatory drug every 8 hours for 10 days. Sixty percent of the drug is removed from the bloodstream every 8 hours. a. Write a recursive rule for the amount of the drug in the bloodstream after \(n\) doses. b. The value that a drug level approaches after an extended period of time is called the maintenance level. What is the maintenance level of this drug given the prescribed dosage? c. How does doubling the dosage affect the maintenance level of the drug? Justify your answer.

In Exercises 33-40, write a rule for the \(n\)th term of the geometric sequence. $$ a_1=1, a_2=49 $$

Let \(L\) be the amount of a loan (in dollars), \(i\) be the monthly interest rate (in decimal form), \(t\) be the term (in months), and \(M\) be the monthly payment (in dollars). a. When making monthly payments, you are paying the loan amount plus the interest the loan gathers each month. For a 1-month loan, \(t=1\), the equation for repayment is \(L(1+i)-M=0\). For a 2-month loan, \(t=2\), the equation is \([L(1+i)-M](1+i)-M=0\). Solve both of these repayment equations for \(L\). b. Use the pattern in the equations you solved in part (a) to write a repayment equation for a \(t\)-month loan. (Hint: \(L\) is equal to \(M\) times a geometric series.) Then solve the equation for \(M\). c. Use the rule for the sum of a finite geometric series to show that the formula in part (b) is equivalent to $$ M=L\left(\frac{i}{1-(1+i)^{-t}}\right) . $$ Use this formula to check your answers in Exercises 57 and 58.

write a rule for the nth term of the arithmetic sequence. \(a_7=58, a_{11}=94\)

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