Chapter 8: Problem 37
Write a recursive rule for the sequence. $$ a_n=-\frac{1}{2}\left(\frac{1}{4}\right)^{n-1} $$
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Chapter 8: Problem 37
Write a recursive rule for the sequence. $$ a_n=-\frac{1}{2}\left(\frac{1}{4}\right)^{n-1} $$
These are the key concepts you need to understand to accurately answer the question.
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write a rule for the nth term of the sequence. Then graph the fi rst six terms of the sequence. \(a_{21}=-25, d=-\frac{3}{2}\)
Tell whether the function represents exponential growth or exponential decay. Then graph the function. \(y=2 e^x\)
The first 8 terms of the geometric sequence $$ -12,-48,-192,-768, \ldots . $$
USING EQUATIONS One term of an arithmetic sequence is \(a_8=-13\). The common difference is \(-8\). What is a rule for the \(n\)th term of the sequence? (A) \(a_n=51+8 n\) (B) \(a_n=35+8 n\) (C) \(a_n=51-8 n\) (D) \(a_n=35-8 n\)
Let a1 = 34. Then write the terms of the sequence until you discover a pattern. $$ a_{n+1}= \begin{cases}\frac{1}{2} a_n, & \text { if } a_n \text { is even } \\\ 3 a_n+1, & \text { if } a_n \text { is odd }\end{cases} $$ Do the same for \(a_1=25\). What can you conclude?
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