Chapter 5: Problem 3
\(f(x)=\sqrt{x+3}\)
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Chapter 5: Problem 3
\(f(x)=\sqrt{x+3}\)
These are the key concepts you need to understand to accurately answer the question.
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\(f(x)=\sqrt[3]{3 x^2-x}\)
MATHEMATICAL CONNECTIONS The surface area \(S\) of a right circular cone with a slant height of 1 unit is given by \(S=\pi r+\pi r^2\), where \(r\) is the radius of the cone. a. Use completing the square to show that $$ r=\frac{1}{\sqrt{\pi}} \sqrt{S+\frac{\pi}{4}}-\frac{1}{2} \text {. } $$ b. Graph the equation in part (a) using a graphing calculator. Then find the radius of a right circular cone with a slant height of 1 unit and a surface area of \(\frac{3 \pi}{4}\) square units.
\(f(x)=x^{1 / 2}, g(x)=\frac{1}{4}(-x)^{1 / 2}\)
\(g(x)=\sqrt{x}-3\)
\(g(x)=-3(x+1)^{1 / 3}\)
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