Chapter 5: Problem 24
\(\frac{\sqrt[4]{4}}{\sqrt[4]{27}}\)
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Chapter 5: Problem 24
\(\frac{\sqrt[4]{4}}{\sqrt[4]{27}}\)
These are the key concepts you need to understand to accurately answer the question.
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In Exercises 49–52, determine whether the functions are inverses. $$ f(x)=7 x^{3 / 2}-4, g(x)=\left(\frac{x+4}{7}\right)^{3 / 2} $$
\(x^2+y^2=9\)
MULTIPLE REPRESENTATIONS The terminal velocity \(v_t\) (in feet per second) of a skydiver who weighs 140 pounds is given by $$ v_t=33.7 \sqrt{\frac{140}{A}} $$ where \(A\) is the cross-sectional surface area (in square feet) of the skydiver. The table shows the terminal velocities (in feet per second) for various surface areas (in square feet) of a skydiver who weighs 165 pounds. \begin{tabular}{|c|c|} \hline Cross-sectional surface area, \(\boldsymbol{A}\) & Terminal velocity, \(\boldsymbol{v}_{\boldsymbol{t}}\) \\ \hline 1 & \(432.9\) \\ 3 & \(249.9\) \\ 5 & \(193.6\) \\ 7 & \(163.6\) \\ \hline \end{tabular} a. Which skydiver has a greater terminal velocity for each value of \(A\) ? b. Describe how the different values of \(A\) given in the table relate to the possible positions of the falling skydiver.
\(f(x)=\sqrt[3]{x^2+x}\)
At the start of a dog sled race in Anchorage, Alaska, the temperature was \(5^{\circ} \mathrm{C}\). By the end of the race, the temperature was \(-10^{\circ} \mathrm{C}\). The formula for converting temperatures from degrees Fahrenheit \(F\) to degrees Celsius \(C\) is \(C=\frac{5}{9}(F-32)\). a. Find the inverse function. Describe what it represents. b. Find the Fahrenheit temperatures at the start and end of the race. c. Use a graphing calculator to graph the original function and its inverse. Find the temperature that is the same on both temperature scales.
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