Chapter 4: Problem 17
\(h(x)=-5 x^4+7 x^3-6 x^2+9 x+2\)
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Chapter 4: Problem 17
\(h(x)=-5 x^4+7 x^3-6 x^2+9 x+2\)
These are the key concepts you need to understand to accurately answer the question.
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Show that the binomial is a factor of the polynomial. Then factor the function completely. $$ s(x)=x^4+4 x^3-64 x-256 ; x+4 $$
ABSTRACT REASONING You are given the function \(f(x)=(x+a)(x+b)(x+c)(x+d)\). When \(f(x)\) is written in standard form, show that the coefficient of \(x^3\) is the sum of \(a, b, c\), and \(d\), and the constant term is the product of \(a, b, c\), and \(d\).
Determine whether the binomial is a factor of the polynomial function. $$ g(x)=8 x^5-58 x^4+60 x^3+140 ; x-6 $$
CRITICAL THINKING Recall that a Pythagorean triple is a set of positive integers \(a, b\), and \(c\) such that \(a^2+b^2=c^2\). The numbers 3,4 , and 5 form a Pythagorean triple because \(3^2+4^2=5^2\). You can use the polynomial identity \(\left(x^2-y^2\right)^2+(2 x y)^2=\left(x^2+y^2\right)^2\) to generate other Pythagorean triples. a. Prove the polynomial identity is true by showing that the simplified expressions for the left and right sides are the same. b. Use the identity to generate the Pythagorean triple when \(x=6\) and \(y=5\). c. Verify that your answer in part (b) satisfies \(a^2+b^2=c^2\)
REASONING Copy Pascal's Triangle and add rows for \(n=6,7,8,9\), and 10 . Use the new rows to expand \((x+3)^7\) and \((x-5)^9\).
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