Chapter 2: Problem 11
\(y=-\frac{1}{4}(x+2)^2+1\)
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Chapter 2: Problem 11
\(y=-\frac{1}{4}(x+2)^2+1\)
These are the key concepts you need to understand to accurately answer the question.
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\(f(x)=(x+6)^2+3\); horizontal shrink by a factor of \(\frac{1}{2}\) and a translation 1 unit down, followed by a reflection in the \(x\)-axis
\(y=\frac{1}{2}(x-3)^2+2\)
. \(y=-4 x^2+8 x+2\)
translation 6 units down followed by a reflection in the \(x\)-axis $$ \begin{aligned} h(x) &=f(x)-6 \\ &=2 x^2+6 x-6 \\ g(x) &=-h(x) \\ &=-\left(2 x^2+6 x-6\right) \\ &=-2 x^2-6 x+6 \end{aligned} $$
USING STRUCTURE Write the quadratic function f(x) = x2 + x ? 12 in intercept form. Graph the function. Label the x-intercepts, y-intercept, vertex, and axis of symmetry.
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