Chapter 7: Problem 88
Determine whether each pair of lines is parallel, perpendicular, or neither $$ 2 x+5 y=-7 \text { and } 5 x-2 y=1 $$
Short Answer
Expert verified
The lines are perpendicular.
Step by step solution
01
Write equations in slope-intercept form
Convert each equation to the slope-intercept form, which is given by \( y = mx + b \), where \( m \) represents the slope.For the first equation, \(2x + 5y = -7\):Subtract \(2x\) from both sides:\[ 5y = -2x - 7 \]Divide by 5:\[ y = \frac{-2}{5}x - \frac{7}{5} \]So, the slope of the first line (\( m_1 \)) is \( \frac{-2}{5} \).
02
Convert the second equation
For the second equation, \(5x - 2y = 1\):Subtract \(5x\) from both sides:\[ -2y = -5x + 1 \]Divide by -2:\[ y = \frac{5}{2}x - \frac{1}{2} \]So, the slope of the second line (\( m_2 \)) is \( \frac{5}{2} \).
03
Determine if lines are parallel, perpendicular, or neither
Compare the slopes of the two lines:1. If the slopes are equal (\( m_1 = m_2 \)), the lines are parallel.2. If the slopes are negative reciprocals (\( m_1 = -\frac{1}{m_2} \)), the lines are perpendicular.3. If the slopes are neither equal nor negative reciprocals, the lines are neither.The first line has a slope of \( \frac{-2}{5} \) and the second line has a slope of \( \frac{5}{2} \).Since \( \frac{-2}{5} = -\frac{1}{ \frac{5}{2}} \), the lines are perpendicular.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
slope-intercept form
The slope-intercept form is a way of writing the equation of a straight line. It is given by the formula:\[ y = mx + b \]Here, 'm' is the slope of the line, and 'b' is the y-intercept, the point where the line crosses the y-axis. Converting an equation to this form helps you easily identify the slope and y-intercept.For example, the equation \(2x + 5y = -7\) can be rearranged to find 'y' by isolating it on one side:1. Subtract '2x' from both sides: \[ 5y = -2x - 7 \]2. Divide every term by 5: \[ y = \frac{-2}{5}x - \frac{7}{5} \]Now the equation is in slope-intercept form, where the slope \(m = \frac{-2}{5}\). This method helps in quickly determining the characteristics of the line in question.>
negative reciprocals
Negative reciprocals are pairs of numbers that, when multiplied together, yield -1. This concept is crucial in determining if two lines are perpendicular.For instance, if you have a slope \(m_1\), the slope of a line that is perpendicular to this line will be \( -\frac{1}{m_1} \).Looking at our example from earlier: 1. The slope of the first line is \( \frac{-2}{5} \).2. The slope of the second line is \( \frac{5}{2} \).We check if they are negative reciprocals by multiplying them together: \( \frac{-2}{5} \times \frac{5}{2} = -1 \).Since the product is -1, the lines are perpendicular. Recognizing negative reciprocals helps us easily determine the relationship between two lines.>
line slopes
Understanding line slopes is fundamental for different aspects of geometry and algebra. The slope of a line measures its steepness and direction, and it's calculated as the rise over the run (change in y over change in x).The slope-intercept form mentioned above gives a straightforward way to find the slope. For example, in the line equation \(y = mx + b\), 'm' is the slope.Slope criteria help us identify whether lines are parallel, perpendicular, or neither:
- Parallel lines have equal slopes (\( m_1 = m_2 \)).
- Perpendicular lines have slopes that are negative reciprocals (\( m_1 = -\frac{1}{m_2} \)).
- Lines that do not meet either criterion are neither parallel nor perpendicular. >Understanding this allows us to categorize the relationships of lines effectively. Applying this to our example, recognizing that one line's slope is \( \frac{-2}{5} \) and the other's is \( \frac{5}{2} \), we determined they are perpendicular due to their slopes being negative reciprocals of each other.>