Chapter 6: Problem 63
Simplify each expression, using only positive exponents in the answer. $$ \frac{x^{-1}+2 y^{-1}}{2 y+4 x} $$
Short Answer
Expert verified
\( \frac{1}{2 y x} \)
Step by step solution
01
- Understand the problem
Given the expression: \( \frac{x^{-1} + 2 y^{-1}}{2 y + 4 x} \), simplify it so that all exponents are positive.
02
- Rewrite negative exponents
Rewrite the terms with negative exponents using positive exponents: \( x^{-1} = \frac{1}{x} \) and \( y^{-1} = \frac{1}{y} \). So the expression becomes: \( \frac{\frac{1}{x} + 2 \frac{1}{y}}{2 y + 4 x} \).
03
- Find common denominator for the numerator
Combine the fractions in the numerator by finding a common denominator: \( \frac{1}{x} + 2 \frac{1}{y} = \frac{y}{xy} + \frac{2x}{xy} = \frac{y + 2x}{xy} \). So the expression now is: \( \frac{\frac{y + 2x}{xy}}{2 y + 4 x} \).
04
- Simplify the complex fraction
Simplify the complex fraction by multiplying the numerator by the reciprocal of the denominator: \( \frac{y + 2x}{xy} \times \frac{1}{2 y + 4 x} \). There is nothing to cancel out, so the simplified form is: \( \frac{y + 2x}{xy(2 y + 4 x)} \).
05
- Simplification
Observe that both the numerator and the denominator have a common factor of \( y + 2x \). Divide both the numerator and the denominator by this common factor to get: \( \frac{1}{2 y x} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Negative Exponents
In algebra, negative exponents can seem tricky at first, but they follow a straightforward rule: any base raised to a negative exponent is the same as the reciprocal of the base with a positive exponent.
For example, \(x^{-1}\) is the same as \(\frac{1}{x} \), and \( y^{-1} \) is equal to \( \frac{1}{y} \).
This rule helps simplify expressions by rewriting them without negative exponents:
For example, \(x^{-1}\) is the same as \(\frac{1}{x} \), and \( y^{-1} \) is equal to \( \frac{1}{y} \).
This rule helps simplify expressions by rewriting them without negative exponents:
- \(x^{-2} = \frac{1}{x^2} \)
- \(a^{-3} = \frac{1}{a^3} \)
- \(b^{-4} = \frac{1}{b^4} \)
Common Denominators
Finding a common denominator is essential for adding and subtracting fractions.
It helps combine fractions into a single fraction. Let's break down this concept using an example:
It helps combine fractions into a single fraction. Let's break down this concept using an example:
- Consider the fractions \( \frac{1}{x} \) and \( \frac{2}{y} \).
- To add \( \frac{1}{x} \) and \( \frac{2}{y} \), find a common denominator, which would be \( xy \).
- Rewrite each fraction with this common denominator: \( \frac{1}{x} = \frac{y}{xy} \) and \( \frac{2}{y} = \frac{2x}{xy} \).
- Combine these: \( \frac{y}{xy} + \frac{2x}{xy} = \frac{y + 2x}{xy} \).
Complex Fractions
A complex fraction is a fraction where the numerator, the denominator, or both, contain fractions themselves.
Simplifying a complex fraction involves a few steps:
\( \frac{1}{2yx} \).
Simplifying a complex fraction involves a few steps:
- Simplify the numerator and the denominator separately.
- Combine them into a single fraction if needed by finding common denominators.
- Multiply the numerator by the reciprocal of the denominator.
- Start with \( \frac{\frac{y + 2x}{xy}}{2y + 4x} \).
- Rewrite by multiplying the numerator by the reciprocal of the denominator: \( \frac{y + 2x}{xy} \times \frac{1}{2y + 4x} \).
- This gives the simplified expression: \( \frac{y + 2x}{xy(2y + 4x)} \).
\( \frac{1}{2yx} \).