Chapter 6: Problem 27
Simplify each complex fraction. Use either method. $$ \frac{\frac{1}{x^{2}}+\frac{1}{y^{2}}}{\frac{1}{x}-\frac{1}{y}} $$
Short Answer
Expert verified
\( \frac{y^{2} + x^{2}}{xy(y - x)} \)
Step by step solution
01
Identify the complex fraction
The given fraction is \( \frac{\frac{1}{x^{2}}+\frac{1}{y^{2}}}{\frac{1}{x}-\frac{1}{y}} \). It has a numerator (\( \frac{1}{x^{2}}+\frac{1}{y^{2}} \)) and a denominator (\( \frac{1}{x}-\frac{1}{y} \)), each of which is a fraction itself.
02
Find the common denominators for the numerator and the denominator
The numerator \( \frac{1}{x^{2}} + \frac{1}{y^{2}} \) has a common denominator of \( x^{2}y^{2} \) and the denominator \( \frac{1}{x} - \frac{1}{y} \) has a common denominator of \( xy \).
03
Combine the fractions in the numerator
To add the fractions in the numerator, use the common denominator \( x^{2}y^{2} \): \( \frac{1}{x^{2}} = \frac{y^{2}}{x^{2}y^{2}} \) \( \frac{1}{y^{2}} = \frac{x^{2}}{x^{2}y^{2}} \) So, \( \frac{1}{x^{2}} + \frac{1}{y^{2}} = \frac{y^{2} + x^{2}}{x^{2}y^{2}} \).
04
Combine the fractions in the denominator
To subtract the fractions in the denominator, use the common denominator \( xy \): \( \frac{1}{x} = \frac{y}{xy} \) \( \frac{1}{y} = \frac{x}{xy} \) So, \( \frac{1}{x} - \frac{1}{y} = \frac{y - x}{xy} \).
05
Divide the combined fractions
Now the complex fraction is \( \frac{\frac{y^{2} + x^{2}}{x^{2}y^{2}}}{\frac{y - x}{xy}} \).To simplify, multiply by the reciprocal of the denominator: \( \frac{y^{2} + x^{2}}{x^{2}y^{2}} \times \frac{xy}{y - x} = \frac{xy(y^{2} + x^{2})}{x^{2}y^{2}(y - x)} = \frac{y^{2} + x^{2}}{xy(y - x)} \).
06
Final simplification
So, the simplified form of the complex fraction is: \( \frac{y^{2} + x^{2}}{xy(y - x)} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
algebraic expressions
In algebra, an algebraic expression is a mathematical phrase that can contain numbers, variables, and operation symbols. Different from a simple arithmetic expression, algebraic expressions include variables such as 'x' or 'y', which can stand for unknown values. For instance, in the problem \[ \frac{\frac{1}{x^{2}}+\frac{1}{y^{2}}}{\frac{1}{x}-\frac{1}{y}} \], complex algebraic expressions are found both in the numerator and denominator. Understanding how to manipulate these expressions is crucial. Remember these points:
- Combine like terms: Terms that have the same variable parts, like \( x^2 \) and \( y^2 \), can often be combined or manipulated using the same steps.
- Use correct operations: Addition, subtraction, multiplication, and division operations must follow algebraic rules.
common denominators
To simplify fractions or complex fractions, finding common denominators is often necessary. A common denominator is a shared multiple of denominators of two or more fractions. Here are some key points about common denominators:
- To add or subtract fractions, they must have the same denominator. For instance, \( \frac{1}{x} \) and \( \frac{1}{y} \) require a common denominator of \( xy \) for subtraction: \[ \frac{y}{xy} - \frac{x}{xy} = \frac{y - x}{xy} \].
- In our exercise, when adding \( \frac{1}{x^2} \) and \( \frac{1}{y^2} \), the common denominator is \( x^2y^2 \): \[ \frac{1}{x^2} + \frac{1}{y^2} = \frac{y^2}{x^2y^2} + \frac{x^2}{x^2y^2} = \frac{y^2 + x^2}{x^2y^2} \].
reciprocal
The reciprocal of a number or expression is what you multiply that number or expression by to get 1. For instance, the reciprocal of \( \frac{a}{b} \) is \( \frac{b}{a} \). When simplifying complex fractions, using the reciprocal is a vital step. Consider these key points:
- To divide by a fraction, multiply by its reciprocal. In our exercise \[ \frac{\frac{y^2 + x^2}{x^2y^2}}{\frac{y - x}{xy}} \], we multiply by the reciprocal of the denominator \[ \frac{y^2 + x^2}{x^2y^2} \times \frac{xy}{y - x} \], which simplifies the problem.
- Using the reciprocal helps cancel out terms and reduce the expression to its simplest form.
For example: \[ \frac{xy(y^2 + x^2)}{x^2y^2(y - x)} \] can be simplified to \[ \frac{y^2 + x^2}{xy(y - x)} \].