Chapter 4: Problem 93
\(\frac{(2 r)^{-4}(2 r)^{5}}{(2 r)^{9}(2 r)^{-7}}\)
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Chapter 4: Problem 93
\(\frac{(2 r)^{-4}(2 r)^{5}}{(2 r)^{9}(2 r)^{-7}}\)
These are the key concepts you need to understand to accurately answer the question.
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The special product \((x+y)(x-y)=x^{2}-y^{2}\) can be used to perform some multiplications.Example: $$\begin{array}{l|l}51 \times 49 & 102 \times 98 \\\=(50+1)(50-1) & =(100+2)(100-2) \\\=50^{2}-1^{2} & =100^{2}-2^{2} \\\=2500-1 & =10,000-4 \\\=2499 & =9996\end{array}$$ Use this method to calculate each product mentally. $$ 30 \frac{1}{3} \times 29 \frac{2}{3} $$
Use scientific notation to calculate the result in each expression. Write answers in scientific notation. 76\. \(\frac{0.000000081(0.000036)}{0.00000048}\)
Find each product. Recall that \(a^{2}=a \cdot a\) and \(a^{3}=a^{2} \cdot a\). $$ 5 k^{2}\left(k^{3}-3\right)\left(k^{2}-k+4\right) $$
In \(2016,\) the U.S. government collected about \(\$ 5712\) per person in individual income taxes. If the population of the United States at that time was 323,000,000 , how much did the government collect in taxes for \(2016 ?\) (Data from www.usgovernmentrevenue.com)
Find each product. Recall that \(a^{2}=a \cdot a\) and \(a^{3}=a^{2} \cdot a\). $$ (8 m+3 n)^{2} $$
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