Chapter 4: Problem 54
Find each product. $$ (y+2)^{3} $$
Short Answer
Expert verified
(y + 2)^3 = y^3 + 6y^2 + 12y + 8
Step by step solution
01
Apply the Binomial Theorem
The Binomial Theorem states that \[ (a + b)^n = \binom{n}{0} a^n b^0 + \binom{n}{1} a^{n-1} b^1 + \binom{n}{2} a^{n-2} b^2 + ... + \binom{n}{n} a^0 b^n \]Here, we can identify \(a = y\), \(b = 2\), and \(n = 3\).
02
Calculate Binomial Coefficients
For \(n = 3\), we need to calculate the coefficients \(\binom{3}{0}\), \(\binom{3}{1}\), \(\binom{3}{2}\), and \(\binom{3}{3}\). These are 1, 3, 3, and 1 respectively.
03
Expand the Terms
Using the binomial coefficients, expand \[ (y + 2)^3 = \binom{3}{0} y^3 2^0 + \binom{3}{1} y^2 2^1 + \binom{3}{2} y^1 2^2 + \binom{3}{3} y^0 2^3 \]which simplifies to \[ (y + 2)^3 = 1 \cdot y^3 + 3 \cdot y^2 \cdot 2 + 3 \cdot y \cdot 4 + 1 \cdot 8 \]
04
Simplify Each Term
Simplify each term to get \[ y^3 + 6y^2 + 12y + 8 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
binomial expansion
The Binomial Theorem is a powerful tool for expanding expressions raised to a power. It allows us to rewrite an expression like \((a + b)^n\) into a sum of terms involving binomial coefficients. This makes complex polynomial expansions much simpler. For example, consider the expression \( (y + 2)^3 \). Applying the Binomial Theorem, we get several terms involving powers of \( y \) and \( 2 \).
The Binomial Theorem states that: \[ (a + b)^n = \binom{n}{0} a^n b^0 + \binom{n}{1} a^{n-1} b^1 + \binom{n}{2} a^{n-2} b^2 + ... + \binom{n}{n} a^0 b^n \] Here, \(a\) and \(b\) are the terms being expanded, and \(n\) is the exponent.
For \( (y + 2)^3 \), \(a = y\), \(b = 2\), and \(n = 3\). Plugging in these values gives us the expanded form.
The Binomial Theorem states that: \[ (a + b)^n = \binom{n}{0} a^n b^0 + \binom{n}{1} a^{n-1} b^1 + \binom{n}{2} a^{n-2} b^2 + ... + \binom{n}{n} a^0 b^n \] Here, \(a\) and \(b\) are the terms being expanded, and \(n\) is the exponent.
For \( (y + 2)^3 \), \(a = y\), \(b = 2\), and \(n = 3\). Plugging in these values gives us the expanded form.
binomial coefficients
Binomial coefficients are essential for calculating individual terms in a binomial expansion. They are represented as \(\binom{n}{k}\), where \(n\) is the total number of terms and \( k \) is the term number. These coefficients can be found using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] where \( n! \) (n factorial) is the product of all positive integers up to \( n \).
For our example \((y + 2)^3\), we need the coefficients for \(n = 3\). This gives us: \[ \binom{3}{0} = 1, \ \binom{3}{1} = 3, \ \binom{3}{2} = 3, \ \binom{3}{3} = 1 \] These coefficients multiply the terms of the binomial expansion, allowing us to write the equation as \[ (y + 2)^3 = \binom{3}{0} y^3 2^0 + \binom{3}{1} y^2 2^1 + \binom{3}{2} y^1 2^2 + \binom{3}{3} y^0 2^3 \].
For our example \((y + 2)^3\), we need the coefficients for \(n = 3\). This gives us: \[ \binom{3}{0} = 1, \ \binom{3}{1} = 3, \ \binom{3}{2} = 3, \ \binom{3}{3} = 1 \] These coefficients multiply the terms of the binomial expansion, allowing us to write the equation as \[ (y + 2)^3 = \binom{3}{0} y^3 2^0 + \binom{3}{1} y^2 2^1 + \binom{3}{2} y^1 2^2 + \binom{3}{3} y^0 2^3 \].
polynomial expansion
Polynomial expansion is the process of expressing a polynomial raised to a power as a sum of simpler terms. The Binomial Theorem helps in breaking down such expressions. For \( (y + 2)^3 \), we use the binomial coefficients calculated earlier and expand the expression step-by-step.
Combining the coefficients with the variables, we get: \[ (y + 2)^3 = 1 \cdot y^3 + 3 \cdot y^2 \cdot 2 + 3 \cdot y \cdot 4 + 1 \cdot 8 \]
Simplifying each term, we arrive at the final expanded polynomial: \[ y^3 + 6y^2 + 12y + 8 \] This expansion makes it easier to work with the polynomial and understand its structure. Each term represents a different power of \( y \), showing how the original binomial is expanded into a sum of simpler components.
Combining the coefficients with the variables, we get: \[ (y + 2)^3 = 1 \cdot y^3 + 3 \cdot y^2 \cdot 2 + 3 \cdot y \cdot 4 + 1 \cdot 8 \]
Simplifying each term, we arrive at the final expanded polynomial: \[ y^3 + 6y^2 + 12y + 8 \] This expansion makes it easier to work with the polynomial and understand its structure. Each term represents a different power of \( y \), showing how the original binomial is expanded into a sum of simpler components.