Chapter 4: Problem 31
\(4^{-3}\)
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Chapter 4: Problem 31
\(4^{-3}\)
These are the key concepts you need to understand to accurately answer the question.
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Find each product. Recall that \(a^{2}=a \cdot a\) and \(a^{3}=a^{2} \cdot a\). $$ (m+6)^{2} $$
In \(2016, \$ 1.14 \times 10^{10}\) was spent to attend motion pictures in the United States and Canada. The total number of tickets sold was 1.32 billion. What was the average ticket price (to the nearest cent) for a movie? (Data from Motion Picture Association of America.)
The special product \((x+y)(x-y)=x^{2}-y^{2}\) can be used to perform some multiplications.Example: $$\begin{array}{l|l}51 \times 49 & 102 \times 98 \\\=(50+1)(50-1) & =(100+2)(100-2) \\\=50^{2}-1^{2} & =100^{2}-2^{2} \\\=2500-1 & =10,000-4 \\\=2499 & =9996\end{array}$$ Use this method to calculate each product mentally. $$ 301 \times 299 $$
Perform each indicated operation. \(\left(8 m^{2}-7 m\right)-\left(3 m^{2}+7 m-6\right)\)
Graph each equation by completing the table of values. $$\begin{aligned} &y=x^{2}-4\\\&\begin{array}{c|c}\hline x & y \\\\\hline-2 & \\\\\hline-1 & \\\\\hline 0 & \\\\\hline 1 & \\\\\hline 2 &\end{array}\end{aligned}$$
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