Chapter 4: Problem 17
\(-(-6)^{0}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 4: Problem 17
\(-(-6)^{0}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Use scientific notation to calculate the result in each expression. Write answers in scientific notation. 75\. \(\frac{0.00000072(0.00023)}{0.000000018}\)
\(\frac{\left(2 y^{-1} z^{2}\right)^{2}\left(3 y^{-2} z^{-3}\right)^{3}}{\left(y^{3} z^{2}\right)^{-1}}\)
\begin{aligned} &\text { Find the difference of the sum of } 5 x^{2}+2 x-3 \text { and } x^{2}-8 x+2 \text { and the sum of } 7 x^{2}-3 x+6\\\ &\text { and }-x^{2}+4 x-6 \end{aligned}
The special product \((x+y)(x-y)=x^{2}-y^{2}\) can be used to perform some multiplications. Example: $$\begin{array}{l|l}51 \times 49 & 102 \times 98 \\\=(50+1)(50-1) & =(100+2)(100-2) \\\=50^{2}-1^{2} & =100^{2}-2^{2} \\\=2500-1 & =10,000-4 \\\=2499 & =9996\end{array}$$ Use this method to calculate each product mentally. $$ 101 \times 99 $$
Perform each indicated operation. \(\left[\left(9 b^{3}-4 b^{2}+3 b+2\right)-\left(-2 b^{3}-3 b^{2}+b\right)\right]-\left(8 b^{3}+6 b+4\right)\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.