Chapter 12: Problem 24
Write in exponential form. \(\log _{64} 2=\frac{1}{6}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 12: Problem 24
Write in exponential form. \(\log _{64} 2=\frac{1}{6}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Solve each equation. Give exact solutions. \(\log _{4}(2 x+8)=2\)
$$ \left(\frac{3}{2}\right)^{x}=\frac{16}{81} $$
To four decimal places, the values of \(\log _{10} 2\) and \(\log _{10} 9\) are $$\log _{10} 2=0.3010 \text { and } \log _{10} 9=0.9542$$ Use these values and the properties of logarithms to evaluate each expression. DO NOT USE A CALCULATOR. $$\log _{10} 36$$
Solve each equation. Use natural logarithms. Approximate solutions to three decimal places when appropriate. $$ \ln e^{2 x}=4 $$
Suppose that you are an agent for a detective agency. Today's encoding function is \(f(x)=4 x-5 .\) Find the rule for \(f^{-1}\) algebraically.
What do you think about this solution?
We value your feedback to improve our textbook solutions.