Chapter 10: Problem 66
\(\sqrt{1500}\)
Short Answer
Expert verified
\( 10 \sqrt{15} \)
Step by step solution
01
Simplify the Expression
First, write the expression in simpler terms by factoring 1500 into its prime factors. Notice that 1500 can be written as 15 * 100.
02
Break Down the Factors
Factorize 15 and 100 further into their prime factors. We get: 15 = 3 * 5 and 100 = 2^2 * 5^2.
03
Combine Prime Factors
Combine all the prime factors of 1500. Therefore, 1500 = 3 * 5 * 2^2 * 5^2, which simplifies to 1500 = 2^2 * 3 * 5^3.
04
Apply the Square Root
Apply the square root to the simplified factorization: \ \ \ \ \ \ \ \ \ \ \(\sqrt{1500} = \sqrt{2^2 * 3 * 5^3}\) \ \ \ \ \ \ This breaks down to \(\sqrt{2^2} * \sqrt{3} * \sqrt{5^3}\).
05
Simplify Further
Evaluate each square root separately: \(\sqrt{2^2} = 2\), \(\sqrt{3} \), and \(\sqrt{5^3} = 5 * \sqrt{5}\). Combining these, we get: \(\sqrt{1500} = 2 * \sqrt{3} * 5* \sqrt{5} \).
06
Final Simplification
Combine the results from the previous step: \(\sqrt{1500} = 2*5 \sqrt{3*5} = 10 \sqrt{15}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Prime Factorization
Prime factorization is the process of expressing a number as the product of prime numbers. For instance, we can break down 1500 into its prime factors: 15 and 100. Then, further decompose these:
- 15 = 3 * 5 (since 3 and 5 are prime)
- 100 = 2^2 * 5^2 (since 2 and 5 are prime)
- 1500 = 2^2 * 3 * 5^3
Simplifying Radicals
Simplifying radicals involves breaking down a square root into its simplest form. Let's simplify \(\root(1500)\). First, use prime factorization: \(\root(2^2 * 3 * 5^3)\). Then, separate terms where possible: \(\root(2^2) * \root(3) * \root(5^3)\).
- \root(2^2) = 2
- \root(3)= \root(3)
- \root(5^3) = 5 * \root(5)
Algebraic Expressions
Algebraic expressions include variables, constants, and operations. When simplifying square roots within these expressions, follow systematic steps. For example: \(\root(2^2 * 3 * 5^3)\) simplifies to \(\root(2^2) * \root(3) * \root(5^3)\), which becomes 2 * \root(3) 5 \root(5). Combining these, we get 10 \root(15). Algebra simplifies radicals and other expressions logically. Follow rules and breakdown steps efficiently to deal with complex problems in mathematics.