Chapter 10: Problem 108
Simplify. Assume that \(x \geq 0\) \(\sqrt[12]{x^{44}}\)
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These are the key concepts you need to understand to accurately answer the question.
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Chapter 10: Problem 108
Simplify. Assume that \(x \geq 0\) \(\sqrt[12]{x^{44}}\)
These are the key concepts you need to understand to accurately answer the question.
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The windchill factor is a measure of the cooling effect that the wind has on a person's skin. It calculates the equivalent cooling temperature if there were no wind. The National Weather Service uses the formula $$ \text { Windchill temperature }=35.74+0.6215 T-35.75 V^{4 / 25}+0.4275 T V^{4 / 25} $$ where T is the temperature in \(^{\circ} \mathrm{F}\) and \(\mathrm{Vi}\) is the wind speed in miles per hour, to calculate wind- chill. The table gives the windchill factor for various wind speeds and temperatures at which frostbite is a risk, and how quickly it may occur. Use the formula to determine the windchill temperature to the nearest tenth of a degree, given the following conditions. Compare answers with the appropriate entries in the table. \(30^{\circ} \mathrm{F}, 15\) -mph wind
Simplify. Assume that all variables represent positive real numbers. \(\sqrt{121 x^{6}}\)
The windchill factor is a measure of the cooling effect that the wind has on a person's skin. It calculates the equivalent cooling temperature if there were no wind. The National Weather Service uses the formula $$ \text { Windchill temperature }=35.74+0.6215 T-35.75 V^{4 / 25}+0.4275 T V^{4 / 25} $$ where T is the temperature in \(^{\circ} \mathrm{F}\) and \(\mathrm{Vi}\) is the wind speed in miles per hour, to calculate wind- chill. The table gives the windchill factor for various wind speeds and temperatures at which frostbite is a risk, and how quickly it may occur. Use the formula to determine the windchill temperature to the nearest tenth of a degree, given the following conditions. Compare answers with the appropriate entries in the table. \(10^{\circ} \mathrm{F}, 30-\mathrm{mph}\) wind
A Panasonic Smart Viera E50 LCD HDTV has a rectangular screen with a 36.5 -in. width. Its height is 20.8 in. What is the length of the diagonal of the screen to the nearest tenth of an inch? (Data from measurements of the author's television.)
Simplify. Assume that all variables represent positive real numbers. \(\sqrt[4]{\frac{1}{16} r^{8} t^{20}}\)
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