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Chapter 8: Problem 15

If 1 pound of turkey costs 2.29 dollar, give an expression for the cost of \(x\) pounds.

Short Answer

Expert verified
2.29x

Step by step solution

01

Identify the unit price

The problem states that 1 pound of turkey costs 2.29 dollars. This is the unit price.
02

Define the variable

Let the variable x represent the number of pounds of turkey.
03

Formulate the expression

To find the cost of x pounds of turkey, multiply the number of pounds (x) by the unit price (2.29 dollars). Therefore, the expression is given by: \[ \text{Cost} = 2.29 \times x \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Price
Unit price is the cost of one unit of a product. In this example, it is the price of 1 pound of turkey. When we are given that 1 pound costs 2.29 dollars, this is the unit price. Understanding unit price is crucial because it allows us to calculate the total cost for any given quantity. For instance, if you wanted to buy 3 pounds of turkey, you would simply multiply the unit price (2.29) by 3 to get the total cost.
Variables
In algebra, we often use variables to represent unknown quantities. A variable is a symbol, often a letter, that stands for a number we don't know yet. In this exercise, we use the variable \(x\) to represent the number of pounds of turkey. When we write an expression, variables allow us to create a formula that can be used for any value. So, if \(x\) represents the pounds of turkey, our formula will work no matter how many pounds we have.
Multiplication
Multiplication is one of the basic operations in mathematics. It combines groups of equal sizes. When we find the cost of \(x\) pounds of turkey, we are essentially adding the unit price \(2.29\) a total of \(x\) times. This is why we multiply the unit price by the variable. The expression \(2.29 \times x\) means we are multiplying 2.29 dollars by the number of pounds represented by \(x\). For example, if \(x = 4\), then the cost is \(2.29 \times 4 = 9.16\) dollars.

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