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91Ó°ÊÓ

Factor completely. \(x^{2}+4 x y+3 y^{2}\)

Short Answer

Expert verified
(x + y)(x + 3y)

Step by step solution

01

Identify the quadratic expression pattern

Recognize that the given expression is a quadratic trinomial: \(x^{2}+4xy+3y^{2}\)
02

Find two numbers that multiply to the constant term and add to the middle coefficient

Look for two numbers that multiply to the constant term (3y^2) and add to the coefficient of the middle term (4y). These numbers are 3y and y, because \(3y \times y = 3y^2\) and \(3y + y = 4y\).
03

Rewrite the middle term

Rewrite the middle term using the two numbers found: \(x^{2}+4xy+3y^{2} = x^{2} + 3xy + yx + 3y^{2}\)
04

Factor by grouping

Group the terms to factor by grouping: \(x^{2} + 3xy + yx + 3y^{2} = x(x + 3y) + y(x + 3y)\)
05

Factor out the common binomial

Factor out the common binomial \(x+3y\): \(x(x + 3y) + y(x + 3y) = (x + y)(x + 3y)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Expressions
A quadratic expression is a polynomial of the form ax^2 + bx + c. In our exercise, we see such an expression with two different variables: x and y. Recognizing the structure of a quadratic trinomial is the first step. The given problem is \(x^{2}+4xy+3y^{2}\), where:
  • \(a = 1\)
  • \(b = 4y\)
  • \(c = 3y^{2}\)

Like all quadratic expressions, our goal is typically to factor them. Factoring transforms a quadratic trinomial into the product of two binomials. This makes it easier to solve equations or further manipulate expressions.
Factor by Grouping
Factoring by grouping is a method that helps break down polynomials by grouping terms with common factors. Let's understand the process with the following steps:
Step 1: Identify the quadratic expression.
Given expression: \(x^{2}+4xy+3y^{2}\).

Step 2: Find two numbers that multiply to the constant term (3y^2) and add to the middle coefficient (4y). In this case, those numbers are 3y and y because:
  • \(3y \times y = 3y^2\)
  • \(3y + y = 4y\)

Step 3: Rewrite the middle term using the numbers found:
\(x^{2}+4xy+3y^{2} = x^{2} + 3xy + yx + 3y^{2}\)
Step 4: Group and factor:
\(x^{2} + 3xy + yx + 3y^{2} = x(x + 3y) + y(x + 3y)\)
Step 5: Factor the common binomial:
\(x(x + 3y) + y(x + 3y) = (x + y)(x + 3y)\).
By following these steps, you can make quadratic trinomials much more manageable.
Polynomial Factorization
Polynomial factorization involves expressing a polynomial as the product of simpler polynomials. Here, we focus on quadratic polynomials.
  • First, recognize if the polynomial is quadratic.
  • Use techniques like finding numbers that multiply to the constant term and add to the coefficient of the middle term (important for quadratics).
  • Utilize methods like factoring by grouping or other appropriate factoring methods depending on the polynomial.
  • Simplify the polynomial into binomials for easier further manipulation.

For our given problem, after grouping, we obtained:
\(x^{2}+4 x y+3 y^{2}=x(x + 3y) + y(x + 3y)\).
Factoring out the common binomial, we get:
\((x + y)(x + 3y)\).
Thus, factorization helps hugely in simplifying and solving polynomial equations efficiently.

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