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Solve each equation. $$ -\frac{5}{6} x=30 $$

Short Answer

Expert verified
x = -36

Step by step solution

01

Isolate the variable

To solve the equation \(-\frac{5}{6} x = 30\), first isolate the variable x. This can be done by multiplying both sides of the equation by the reciprocal of \(-\frac{5}{6}\), which is \(-\frac{6}{5}\).
02

Multiply both sides

Multiply both sides of the equation by \(-\frac{6}{5}\): \(-\frac{5}{6} x \times -\frac{6}{5} = 30 \times -\frac{6}{5}\)
03

Simplify the left side

On the left side, the \(-\frac{5}{6}\) and \(-\frac{6}{5}\) terms will cancel each other out, leaving just x: \(x = 30 \times -\frac{6}{5}\)
04

Calculate the right side

Perform the multiplication on the right side: \(30 \times -\frac{6}{5} = -36\)
05

Solution

Thus, the solution to the equation is \(x = -36\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isolating Variables
When solving linear equations like \(-\frac{5}{6} x = 30\), the first step often involves isolating the variable you are solving for, which is x in this case.
  • To isolate x, you need to get rid of any coefficients or constants that are multiplied or added to x on one side of the equation.
  • In the given equation, x is multiplied by \(-\frac{5}{6}\).
  • By isolating the variable, you'll be left with x on one side of the equation, making it easier to solve.
In this example, isolating x requires multiplying both sides by the reciprocal of \(-\frac{5}{6}\). This leads us to our next core concept: reciprocal multiplication.
Reciprocal Multiplication
Reciprocal multiplication is a key technique in solving linear equations. The reciprocal of a number is essentially 1 divided by that number.
  • For a fraction, its reciprocal simply flips the numerator and the denominator. So, the reciprocal of \(-\frac{5}{6}\) is \(-\frac{6}{5}\).
  • When you multiply a number with its reciprocal, the result is always 1. This is because the multiplication of a number by its reciprocal cancels out the fraction.
In our equation \(-\frac{5}{6} x = 30\), this means multiplying both sides by \(-\frac{6}{5}\) to isolate x:
\[ -\frac{5}{6} x \times -\frac{6}{5} = 30 \times -\frac{6}{5} \] This multiplication will cancel out \(-\frac{5}{6}\) on the left side, leaving us with x on its own.
Simplifying Algebraic Expressions
Simplifying algebraic expressions is crucial for solving equations efficiently. Cleaning up these expressions makes it easier to see the solution.
  • In our example, once we perform the multiplication on both sides, we simplify the left side.
  • The terms \(-\frac{5}{6}\) and \(-\frac{6}{5}\) cancel each other out because their product is 1.
This is shown as follows:
\[ -\frac{5}{6} x \times -\frac{6}{5} = x \] Leaving us with:
\[ x = 30 \times -\frac{6}{5} \] With x isolated, we now focus on multiplying the right side and simplifying it.
Negative Reciprocals
Understanding negative reciprocals is important as it often appears in algebraic manipulations.
  • The negative reciprocal of a fraction is achieved by flipping the fraction and changing the sign. So, the negative reciprocal of \(\frac{5}{6}\) is \(-\frac{6}{5}\).
  • In the equation, we used the negative reciprocal \(-\frac{6}{5}\) to make sure the negative sign is also effectively handled.
So, multiplying both sides of the equation \(-\frac{5}{6} x = 30\) by \(-\frac{6}{5}\) takes care of both the fraction and the negative sign.

Finally, after solving, we end up with the solution:
\[ x = -36 \] Understanding these concepts helps solve linear equations efficiently and correctly.

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