Chapter 11: Problem 10
Use the quadratic formula to solve each equation. (All solutions for these equations are real numbers.) $$ 9 x^{2}+6 x=1 $$
Short Answer
Expert verified
The solutions to the equation are \(x = \frac{-1 + \sqrt{2}}{3}\) and \(x = \frac{-1 - \sqrt{2}}{3}\).
Step by step solution
01
Write the equation in standard form
First, we need to rearrange the equation so that it is in the standard quadratic form: \[ ax^2 + bx + c = 0 \]Starting with: \[ 9x^2 + 6x = 1 \]Subtract 1 from both sides:\[ 9x^2 + 6x - 1 = 0 \]
02
Identify coefficients
Next, identify the coefficients from the quadratic equation in standard form. In this case:\[ a = 9, \ b = 6, \ c = -1 \]
03
Write down the quadratic formula
The quadratic formula is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
04
Substitute coefficients into the quadratic formula
Substitute the values of \( a \), \( b \), and \( c \) into the quadratic formula:\[ x = \frac{-6 \pm \sqrt{6^2 - 4(9)(-1)}}{2(9)} \]
05
Simplify under the square root
Calculate the value under the square root:\[ 6^2 = 36 \]\[ -4(9)(-1) = 36 \]So the expression under the square root becomes:\[ 36 + 36 = 72 \]Then:\[ x = \frac{-6 \pm \sqrt{72}}{18} \]
06
Simplify the square root
Simplify \( \sqrt{72} \):\[ \sqrt{72} = \sqrt{36 \times 2} = 6\sqrt{2} \]So the equation becomes:\[ x = \frac{-6 \pm 6\sqrt{2}}{18} \]
07
Simplify the fraction
Factor out a 6 from the numerator:\[ x = \frac{6(-1 \pm \sqrt{2})}{18} \]Reduce the fraction:\[ x = \frac{-1 \pm \sqrt{2}}{3} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic formula
When faced with a quadratic equation, one helpful tool is the quadratic formula. This formula gives us the roots (solutions) directly without requiring factorization. The quadratic formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] The components of the formula come from the standard quadratic equation format, which is in the form of \[ ax^2 + bx + c = 0 \].
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
- One solution with addition
- One solution with subtraction
standard form
To use the quadratic formula, we first need to express our equation in the standard form \[ ax^2 + bx + c = 0 \]. In our exercise, we start with \[ 9x^2 + 6x = 1 \]. To convert this into the standard form, we subtract 1 from both sides to get: \[ 9x^2 + 6x - 1 = 0 \]. Now we can identify the coefficients:
- a = 9
- b = 6
- c = -1
solving quadratic equations
Once we have the equation in standard form, solving it with the quadratic formula becomes a systematic task. Using the coefficients from our example (\[ a = 9 \],\[ b = 6 \],\[ c = -1 \]), we substitute them into the quadratic formula: \[ x = \frac{-6 \pm \sqrt{6^2 - 4\cdot 9 \cdot (-1)}}{2\cdot 9} \]. Next, we simplify the expression inside the square root (discriminant):
- \[ 6^2 = 36 \]
- \[ -4 \cdot 9 \cdot (-1) = 36 \]
- \[ 36 + 36 = 72 \]