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If \(y\) varies inversely as \(x,\) find the constant of variation and the inverse variation equation for each situation. See Example \(3 .\) $$ y=\frac{1}{10} \text { when } x=40 $$

Short Answer

Expert verified
The constant of variation is 4; the equation is \(y = \frac{4}{x}\).

Step by step solution

01

Understanding Inverse Variation

When a variable \(y\) varies inversely as \(x\), it means there is some constant \(k\) such that \(y \cdot x = k\). This relationship is summarized by the equation \(y = \frac{k}{x}\). The task is to find this constant \(k\) and write the inverse variation equation.
02

Substitute Known Values

Given that \(y = \frac{1}{10}\) when \(x = 40\), substitute these values into the equation \(y \cdot x = k\) to find \(k\). So, calculate \(\frac{1}{10} \times 40 = k\).
03

Calculate the Constant of Variation

Perform the multiplication: \(\frac{1}{10} \times 40 = 4\). Thus, the constant of variation \(k\) is 4.
04

Write the Inverse Variation Equation

Now that \(k = 4\), substitute \(k\) back into the inverse variation equation \(y = \frac{k}{x}\) to get \(y = \frac{4}{x}\). This is the equation representing the inverse variation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant of Variation
When you encounter a problem involving inverse variation, one of the first things you'll need to identify is the constant of variation, often denoted by the letter \( k \). In an inverse variation, if one variable increases, the other decreases in such a way that their product is always constant. This constant is what we refer to as the constant of variation.

For example, if you're given that \( y = \frac{1}{10} \) when \( x = 40 \), to find \( k \), you multiply \( y \) and \( x \) together:
  • \( y \cdot x = k \)
  • \( \frac{1}{10} \cdot 40 = 4 \)
So, the constant of variation \( k \) is 4. This means no matter how \( x \) or \( y \) changes, their product will always be 4 in this particular situation.
Inverse Variation Equation
Once you have determined the constant of variation \( k \), you can easily construct the inverse variation equation. This equation is used to describe how one variable behaves in relation to another through inverse variation.

The general form of an inverse variation equation is:
  • \( y = \frac{k}{x} \)
With \( k = 4 \) from our example, the equation becomes \( y = \frac{4}{x} \). This formula helps predict the value of \( y \) for any given \( x \), assuming the inverse relationship holds.

If \( x \) becomes larger, \( y \) will become smaller, while \( y \) will grow as \( x \) shrinks, maintaining the constant product of 4.
Algebraic Relationships
In the world of algebra, understanding how variables interact in different ways is crucial. Inverse variation is just one type of relationship, distinct from direct variation, where variables increase or decrease together.

In an inverse relationship:
  • As one variable increases, the other decreases.
  • Their product remains constant.
This is why it's designed as \( y \cdot x = k \). Compare this to direct variation, where the equation \( y = kx \) shows how \( y \) changes in direct proportion to \( x \).

Recognizing these differences helps in accurately modeling real-world phenomena. Whether estimating fuel efficiency as speed changes, calculating pressure and volume in gases, or exploring other inverse relationships, grasping these concepts cements a strong foundation in algebraic thinking.

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Most popular questions from this chapter

The value of a computer bought in 2003 depreciates, or decreases, as time passes. Two years after the computer was bought, it was worth \(\$ 2000 ; 4\) years after it was bought, it was worth \(\$ 800\) a. If this relationship between number of years past 2003 and value of computer is linear. write an equation describing this relationship. IUse ordered pairs of the form (years past \(2003 \text { , value of computer }) \cdot 1\) b. Use this equation to estimate the value of the computer in the year 2008 .

In \(2006,\) the median price of an existing home in the United States was approximately \(\$ 222,000 .\) In 2001 , the median price of an existing home was \(\$ 150,900 .\) Let \(y\) be the median price of an existing home in the year \(x\), where \(x=0\) represents \(2001 .\) (Source: National Association of REALTORS") a. Write a linear equation that models the median existing home price in terms of the year \(x\). [ Hint: The line must pass through the points \((0,150,900)\) and \((5,22,000) .1\) b. Use this equation to predict the median existing home price for the year 2010 . c. Interpret the slope of the equation found in part a.

Describe how to check to see if the graph of \(2 x-4 y=7\) passes through the points \((1.4,-1.05)\) and \((0 .-1.75) .\) Then follow your directions and check these points.

Simplify. $$ -|7| $$

Write an equation to describe each variation. Use \(k\) for the constant of proportionality. See Examples I through \(7 .\) \(y\) varies directly as \(a^{5}\) and inversely as \(b\)

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