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91Ó°ÊÓ

Perform each indicated operation. $$ \frac{9}{9}-\frac{19}{9} $$

Short Answer

Expert verified
\( \frac{-10}{9} \)

Step by step solution

01

Identify the Operation

The operation given in the exercise is a subtraction of two fractions: \( \frac{9}{9} - \frac{19}{9} \).
02

Ensure Common Denominator

Both fractions already have a common denominator, which is 9. This means we can directly subtract the numerators.
03

Subtract the Numerators

Subtract the numerators of the fractions: \( 9 - 19 = -10 \).
04

Form the Resulting Fraction

The result of the subtraction is \( \frac{-10}{9} \). We place the numerator over the common denominator from the original fractions.
05

Simplify if Necessary

Check to see if the fraction \( \frac{-10}{9} \) can be simplified. In this case, it cannot be simplified further since 10 and 9 are coprime.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Denominator
In the world of fraction operations, having a common denominator is your best friend. When subtracting fractions such as \( \frac{9}{9} \) and \( \frac{19}{9} \), you're in luck because they already share a common denominator, in this case, 9. This denominator indicates the same 'whole' that both fractions are part of.

A common denominator is crucial because it allows straightforward subtraction or addition of fractions. Without it, you would first need to convert fractions to have common denominators, often finding the least common multiple (LCM).

In our example, since both fractions already have the denominator 9, you can move straight to focusing on the numerators, making subtraction much simpler. Your main task becomes subtracting the numerators while keeping the denominator intact.
Numerator Subtraction
Once you've established a common denominator, it's time to subtract the numerators from each other; think of it as taking away portions of the same sized 'pizzas'.

In the exercise, you need to subtract the numerator of the second fraction from the first: \( 9 - 19 \). This will result in \( -10 \). Notice that this produces a negative result because the first fraction's numerator is smaller than the second.

Subtracting numerators is straightforward when they share a common denominator. Just manage the top numbers and let your denominator do the hard work of keeping everything consistent. Also, be sure to keep the sign correct after subtraction to ensure a proper result.
Simplify Fractions
After calculating the numerator, you have the fraction \( \frac{-10}{9} \). The last step is always to check if you can simplify the fraction. Simplifying means reducing the fraction to its simplest form.

To do this, you look for the greatest common divisor (GCD) of the numerator and denominator. If there is any, divide both the numerator and the denominator by the GCD. In our case, \( -10 \) and \( 9 \) are coprime, meaning they do not share any common factors other than 1.

Thus, \( \frac{-10}{9} \) is already in its simplest form. Simplifying fractions not only makes them neater but also easier to understand at a glance. Always double-check to see if a fraction can be simplified as it’s a valuable habit.

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Most popular questions from this chapter

One of the great algebraists of ancient times a man named Diophantus. Litle is known of his life other than the lived and worked in Alexandria. Some historians believe he lived during the first century of the Christian era, about the time of Nero. The only che to his personal life is the following epigram found in a collection called the Palatine A nthology. God granted him youth for a sixth of his life and added a twelfth part to this. He clothed his cheeks in down. He lit him the light of wedlock after a seventh part and five years after his marriage. He granted him a son. Alas, lateborn wretched child. After attaining the measure of half his father's life, cruel fate overtook him, thus leaving Diophantus during the last four years of his life only such consolation as the science of numbers. How old was Diophantus at his death?" We are looking for Diophantus' age when he died, so let x represent that age. If we sum the parts of his life, we should get the total age. Parts of his life \(\left\\{\begin{array}{l}{\frac{1}{6} x+\frac{1}{12} x \text { is the time of his youth. }} \\ {\frac{1}{7} x \text { is the time between his youth and when }} \\ {\text { he married. }} \\ {5 \text { years is the time between his marriage }} \\ {\text { and the birth of his son. }} \\\ {\frac{1}{2} x \text { is the time Diophantus had with his son. }} \\ {4 \text { years is the time between his son's death }} \\ {\text { and his own. }}\end{array}\right.\) The sum of these parts should equal Diophantus' age when he died. $$ \frac{1}{6} \cdot x+\frac{1}{12} \cdot x+\frac{1}{7} \cdot x+5+\frac{1}{2} \cdot x+4=x $$ Solve the epigram.

Simplify each complex fraction. See Examples 1 and 2. $$ \frac{\frac{x+3}{x^{2}-9}}{1+\frac{1}{x-3}} $$

Perform each indicated operation. See Section 1.3. $$ \frac{13}{20} \div \frac{2}{9} $$

Solve the following linear and quadratic equations. See Sections 2.3 and 6.6 $$ 2(3 x+1)+15=-7 $$

Solve. See the Concept Check in the Section. Which of the following are equivalent to \(\frac{\frac{a}{7}}{\frac{b}{13}} ?\) a. \(\frac{a}{7} \cdot \frac{b}{13}\) b. \(\frac{a}{7} \div \frac{b}{13}\) c. \(\frac{a}{7} \div \frac{13}{b}\) d. \(\frac{a}{7} \cdot \frac{13}{b}\)

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