Chapter 7: Problem 55
Solve the following. See Section 3.6. If \(P(x)=-x^{2},\) find \(P(-3)\).
Short Answer
Expert verified
The value of \(P(-3)\) is \(-9\).
Step by step solution
01
Understanding the Problem
We need to evaluate the function \(P(x) = -x^2\) at \(x = -3\). This means we replace every instance of \(x\) in the function with \(-3\).
02
Substitute the Value into the Function
Substitute \(x = -3\) into the function. This gives us \(P(-3) = -(-3)^2\).
03
Evaluate the Expression
Calculate \((-3)^2\): \[(-3)^2 = 9\]Then, find \(-(-3)^2\) which is \(-9\). The negative sign in front of the squared term means we take the negative of 9.
04
State the Result
Therefore, the value of \(P(-3)\) is \(-9\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful tool in mathematics used for function evaluation. When we want to find the value of a function at a specific point, we "substitute" this point into the function. For example, in our exercise, we had the function \(P(x) = -x^2\). We wanted to find the value when \(x = -3\). This means we replace every occurrence of \(x\) in the function with \(-3\).
This turns \(P(x) = -x^2\) into \(P(-3) = -(-3)^2\). By substituting, we transform a variable expression into a numerical one, allowing us to evaluate it. The substitution method makes things easier by simplifying and reducing complex expressions to particular instances.
This turns \(P(x) = -x^2\) into \(P(-3) = -(-3)^2\). By substituting, we transform a variable expression into a numerical one, allowing us to evaluate it. The substitution method makes things easier by simplifying and reducing complex expressions to particular instances.
- Identify the point of evaluation.
- Replace the variable in the function with this point.
- Solve the now numerical expression.
Quadratic Functions
Quadratic functions are a type of polynomial function characterized by the term involving \(x^2\). This makes them parabolas when graphed on a coordinate plane. In general terms, a quadratic function can be written as \(f(x) = ax^2 + bx + c\), where \(a, b,\) and \(c\) are constants.
In our specific case, the function \(P(x) = -x^2\) is a simple quadratic without the linear \(bx\) or constant \(c\) terms. The coefficient of \(x^2\) is \(-1\), which influences the shape and direction of the parabola. A negative coefficient, like \(-1\) in this function, inverts the parabola, making it open downwards.
In our specific case, the function \(P(x) = -x^2\) is a simple quadratic without the linear \(bx\) or constant \(c\) terms. The coefficient of \(x^2\) is \(-1\), which influences the shape and direction of the parabola. A negative coefficient, like \(-1\) in this function, inverts the parabola, making it open downwards.
- The highest power of \(x\) is 2, marking it as quadratic.
- The direction of the parabola can be upwards or downwards.
- The constant \(a\) affects the "wideness" and orientation of the parabola.
Negative Numbers
Negative numbers often involve complexities when squared or placed in functions. In our exercise \(P(x) = -x^2\), we dealt with \(-3\) as the input.
Squaring a negative number, such as \(-3\), results in a positive number. The rule \((-a)^2 = a^2\) applies because the negative sign is affected by the squaring. For \((-3)^2\), it's essentially \(-3 \times -3 = 9\).
However, since\(P(x)\) has a negative sign before \(x^2\), it re-introduces negativity back, producing \(-9\) as the final outcome.
Squaring a negative number, such as \(-3\), results in a positive number. The rule \((-a)^2 = a^2\) applies because the negative sign is affected by the squaring. For \((-3)^2\), it's essentially \(-3 \times -3 = 9\).
However, since\(P(x)\) has a negative sign before \(x^2\), it re-introduces negativity back, producing \(-9\) as the final outcome.
- Squaring a negative results in a positive.
- Extra negative signs preceding expressions revert outcomes.
- Always perform operations in steps to avoid errors.