Chapter 6: Problem 19
Factor each trinomial completely. If a polynomial can't be factored, write "prime." See Examples I through 8 . $$ 10 t-24+t^{2} $$
Short Answer
Expert verified
The factored form is \((t + 12)(t - 2)\).
Step by step solution
01
Write the Polynomial in Standard Form
To begin factoring the trinomial, we first need to express it in standard quadratic form \(ax^2 + bx + c\). Rearranging the given expression \(t^2 + 10t - 24\) gives us the trinomial in standard form: \(t^2 + 10t - 24\). This puts the coefficients in their respective places: \(a = 1\), \(b = 10\), and \(c = -24\).
02
Identify a Pair of Numbers
Next, we need to find two numbers that multiply to \(a \cdot c\) (i.e., \(1 \cdot -24 = -24\)) and add up to \(b\) (i.e., 10). The numbers that satisfy both conditions are 12 and -2 because \(12 \times (-2) = -24\) and \(12 + (-2) = 10\).
03
Rewrite the Middle Term
Using the numbers found in the previous step (12 and -2), we split the middle term (10t) of the trinomial into two separate terms. Rewrite the trinomial as \(t^2 + 12t - 2t - 24\).
04
Factor by Grouping
Now, we factor by grouping. Take the first two terms \(t^2 + 12t\) and factor out \(t\), giving us \(t(t + 12)\). Then, take the last two terms \(-2t - 24\) and factor out \(-2\), giving us \(-2(t + 12)\).
05
Extract the Common Factor
Notice that \((t + 12)\) is a common factor in both groups. Factor \((t + 12)\) out to get \((t + 12)(t - 2)\). This is the completely factored form of the original trinomial.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a polynomial equation of degree 2. That means the highest exponent on the variable is 2. The general form of a quadratic equation is \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants, with \(a eq 0\).
In the quadratic expression from the exercise, we start with \(t^2 + 10t - 24\). This is already in a standard quadratic form, with \(a = 1\), \(b = 10\), and \(c = -24\).
In the quadratic expression from the exercise, we start with \(t^2 + 10t - 24\). This is already in a standard quadratic form, with \(a = 1\), \(b = 10\), and \(c = -24\).
- The \(t^2\) term tells us the equation is quadratic.
- The linear term, 10t, contributes to the equation's shape and direction.
- The constant term \(-24\) shifts the parabola up or down the y-axis.
Polynomial Factoring
Polynomial factoring involves expressing a polynomial as a product of its factors. In simpler terms, it's about breaking down a polynomial into simpler parts that, when multiplied together, give back the original polynomial.
Factoring is very helpful in many algebraic processes, especially when solving quadratic equations. When factoring trinomials—like \(t^2 + 10t - 24\)—the goal is to find two binomials whose product is the original trinomial.
Factoring is very helpful in many algebraic processes, especially when solving quadratic equations. When factoring trinomials—like \(t^2 + 10t - 24\)—the goal is to find two binomials whose product is the original trinomial.
- In our context, after rewriting the polynomial in standard form, we found numbers that satisfy two conditions: multiplying to \(a \cdot c\) and adding to \(b\).
- In this case, the numbers found were 12 and -2, which allowed a breakdown of the middle term for easier factoring.
Factoring by Grouping
Factoring by grouping is a technique used to factor polynomials, typically when there are four terms. It involves arranging terms in such a way that certain groups of terms share a common factor.
In the given quadratic Polynomial, once the middle term was split into 12t and -2t, the polynomial became \(t^2 + 12t - 2t - 24\).
In the given quadratic Polynomial, once the middle term was split into 12t and -2t, the polynomial became \(t^2 + 12t - 2t - 24\).
- This four-term polynomial can be split into two groups: \(t^2 + 12t\) and \(-2t - 24\).
- Factoring out a common factor from each group gave \(t(t + 12)\) and \(-2(t + 12)\).
- Recognizing \(t+12\) as a common factor in both groups allows for further simplification to \((t + 12)(t - 2)\).