Chapter 6: Problem 118
Find a positive value of \(b\) so that each trinomial is factorable. \(2 y^{2}+b y+3\)
Short Answer
Expert verified
The positive value of \(b\) that makes the trinomial factorable is 5.
Step by step solution
01
Set up the problem
We have the trinomial \(2y^2 + by + 3\). We need to find a value for \(b\) such that the trinomial is factorable.
02
Identify factorable conditions
A quadratic trinomial \(ax^2 + bx + c\) is factorable with integer coefficients if the discriminant \(b^2 - 4ac\) is a perfect square. This makes the expression have rational roots.
03
Apply factorability condition
For the trinomial \(2y^2 + by + 3\), substitute \(a = 2\), \(b = b\), and \(c = 3\) into the discriminant formula: \[ b^2 - 4ac = b^2 - 4 \cdot 2 \cdot 3 = b^2 - 24 \] This must be a perfect square.
04
Solve for the perfect square condition
To find the suitable \(b\), solve \(b^2 - 24 = k^2\) for some integer \(k\). This implies: \[ b^2 = k^2 + 24 \] We need to find integer solutions \(b\) such that \(k^2 + 24\) is a perfect square.
05
Test integer values for k
Test small integer values for \(k\) starting from 0 and incrementing, to find when \(k^2 + 24\) becomes a perfect square.- For \(k=0\), \(k^2 + 24 = 24\), not a perfect square.- For \(k=1\), \(k^2 + 24 = 25\), which is a perfect square \((5^2)\).
06
Determine corresponding b value
Using \(k=1\), since \(b^2 = k^2 + 24\), it follows \[ b^2 = 1^2 + 24 = 25 \] Therefore, \(b = 5\) (as we need a positive \(b\)).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is any equation that can be rearranged in standard form as:
- \(ax^2 + bx + c = 0\)
- \(ax^2 + bx + c\)
Discriminant
The discriminant is a special numeric value that tells you about the nature of the roots of a quadratic equation. For the equation \(ax^2 + bx + c = 0\), the discriminant \(D\) is defined as:
- \(b^2 - 4ac\)
- If \(D > 0\), the equation has two distinct real roots.
- If \(D = 0\), there is exactly one real root (a repeated root).
- If \(D < 0\), there are no real roots, only complex numbers.
Perfect Square
A perfect square is an integer that is the square of another integer. For example, 1, 4, 9, 16, and 25 are perfect squares because:
When testing integers for \(b^2 = k^2 + 24\), if we find that a specific \(k^2 + 24\) equals a perfect square, it means our required condition is met. In this case, testing \(k=1\) gave \(k^2 + 24 = 25\), which is a perfect square (since \(5^2 = 25\)), leading us to \(b = 5\). These steps help us identify the correct structure needed for factorable trinomials.
- \(1 = 1^2\)
- \(4 = 2^2\)
- \(9 = 3^2\)
- \(16 = 4^2\)
- \(25 = 5^2\)
When testing integers for \(b^2 = k^2 + 24\), if we find that a specific \(k^2 + 24\) equals a perfect square, it means our required condition is met. In this case, testing \(k=1\) gave \(k^2 + 24 = 25\), which is a perfect square (since \(5^2 = 25\)), leading us to \(b = 5\). These steps help us identify the correct structure needed for factorable trinomials.