Chapter 5: Problem 39
Multiply. See Example 7. $$ (3 a+1)^{2} $$
Short Answer
Expert verified
The expanded form is \(9a^2 + 6a + 1\).
Step by step solution
01
Understand the Problem
Our goal is to expand the expression \((3a + 1)^2\). This means we need to multiply the expression \((3a + 1)\) by itself.
02
Apply the Formula for Squaring a Binomial
Recall the formula \((x + y)^2 = x^2 + 2xy + y^2\). In this problem, \(x = 3a\) and \(y = 1\). Substitute these into the formula.
03
Calculate \(x^2\)
Computing \((3a)^2\) gives us \(9a^2\) because \(3a \times 3a = 9a^2\).
04
Calculate \(2xy\)
The term \(2xy\) is \(2 \times 3a \times 1\). Calculate this to get \(6a\).
05
Calculate \(y^2\)
The term \(y^2\) is simply \(1^2\), which equals 1.
06
Combine All Terms
We now combine all the terms: \(9a^2 + 6a + 1\) to form the expanded expression.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Squaring a Binomial
When we square a binomial, we mean multiplying it by itself. A binomial has two terms, like x + y. Squaring it involves applying the formula:
If you have a binomial (3a + 1), squaring it means you multiply (3a + 1) by itself. This leads to three specific tasks:
- \((x + y)^2 = x^2 + 2xy + y^2\).
If you have a binomial (3a + 1), squaring it means you multiply (3a + 1) by itself. This leads to three specific tasks:
- Calculate the square of the first term \(3a\), giving \(9a^2\).
- Calculate double the product of the two terms, \(2 imes 3a imes 1 = 6a\), the middle term.
- Finally, square the second term \(1\) to get \(1\).
Algebraic Expressions
An algebraic expression includes numbers, variables, and operations. When squaring a binomial like
(3a + 1),
we work with algebraic expressions. They are fundamental in algebra because they represent quantities in different forms.
Breaking down (3a + 1)^2 into understandable pieces helps us grasp the concept of expressions:
Breaking down (3a + 1)^2 into understandable pieces helps us grasp the concept of expressions:
- 3a represents a variable a multiplied by a coefficient 3.
- The constant 1 adds a fixed value to the expression.
- Operators like addition or multiplication are used to combine these parts.
Polynomial Multiplication
Polynomial multiplication extends what we've done when squaring a binomial. A polynomial can have more terms, like (x^2 + 2x + 1). Multiplying polynomials involves distributing each term of one polynomial across every term of the other polynomial.
When squaring a binomial (3a + 1), we perform multiplication contained within polynomials:
This process of multiplying each element highlights how multiplication of polynomials incorporates rules of distribution and simplification to handle more complex algebraic forms.
When squaring a binomial (3a + 1), we perform multiplication contained within polynomials:
- Distribute 3a to both 3a and 1, calculating
- \(3a imes 3a = 9a^2\), and \(3a imes 1 = 3a\).
- Next, distribute 1 to both 3a and 1, resulting in \(1 imes 3a = 3a\) and \(1 imes 1 = 1\).
This process of multiplying each element highlights how multiplication of polynomials incorporates rules of distribution and simplification to handle more complex algebraic forms.