Chapter 4: Problem 64
Given the system of linear equations \(\left\\{\begin{array}{l}{3 x-y=-8} \\\ {5 x+3 y=2}\end{array}\right.\) Use the addition method and a. Solve the system by eliminating \(x\). b. Solve the system by eliminating \(y .\)
Short Answer
Expert verified
\( x = -\frac{11}{7} \), \( y = \frac{23}{7} \).
Step by step solution
01
Identify equations
We have two equations given: \( 3x - y = -8 \) and \( 5x + 3y = 2 \). We will begin by eliminating \( x \) first.
02
Eliminate x
To eliminate \( x \), let's make the coefficients of \( x \) in both equations equal by multiplying the first equation by 5 and the second equation by 3. This gives us the equations: \( 15x - 5y = -40 \) and \( 15x + 9y = 6 \).
03
Subtract equations
Subtract the second modified equation from the first: \( (15x - 5y) - (15x + 9y) = -40 - 6 \). Simplifying gives us \( -14y = -46 \).
04
Solve for y
Divide both sides by -14: \( y = \frac{46}{14} = \frac{23}{7} \).
05
Substitute y into original equation to find x
Substitute \( y = \frac{23}{7} \) back into the first original equation \( 3x - y = -8 \): \( 3x - \frac{23}{7} = -8 \). Solve for \( x \): \( 3x = -8 + \frac{23}{7} \). Multiply by 7 to clear fractions: \( 21x = -56 + 23 \), which gives \( 21x = -33 \), so \( x = -\frac{11}{7} \).
06
Re-identify equations for eliminating y
Now, we solve by eliminating \( y \). We use the original equations: \( 3x - y = -8 \) and \( 5x + 3y = 2 \).
07
Adjust coefficients to eliminate y
To eliminate \( y \), multiply the first equation by 3: \( 9x - 3y = -24 \). Use the second equation as is: \( 5x + 3y = 2 \).
08
Add equations
Add the two equations: \( (9x - 3y) + (5x + 3y) = -24 + 2 \). Simplifying gives \( 14x = -22 \).
09
Solve for x
Divide both sides by 14: \( x = -\frac{11}{7} \).
10
Substitute x into original equation to find y
Substitute \( x = -\frac{11}{7} \) back into the first original equation \( 3x - y = -8 \): \( 3(-\frac{11}{7}) - y = -8 \). Solve for \( y \): \( -\frac{33}{7} - y = -8 \), \( -y = -8 + \frac{33}{7} \), \( -y = \frac{-56 + 33}{7} \), so \( -y = \frac{-23}{7} \), therefore \( y = \frac{23}{7} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Addition Method
The addition method is a compelling technique used to solve systems of linear equations. It focuses on combining equations to cancel out a specific variable, making it easier to solve for the remaining ones. This approach involves three key steps:
- Align the equations properly so corresponding terms are stacked vertically.
- Adjust the coefficients of the variable you want to eliminate so they are equal in both equations, but with opposite signs.
- Add or subtract the equations to eliminate one variable, simplifying the system to a single equation.
Elimination Method
The elimination method, closely related to the addition method, efficiently removes certain variables to simplify solving systems. It's a strategic approach that requires no graphing, relying instead on algebraic manipulation.Here's how it works:
- Focus on one variable to eliminate. Choose the one that seems easiest based on coefficients.
- Multiply the equations by necessary factors so that the chosen variable has opposite coefficients in each equation.
- Add or subtract the equations to remove one variable, simplifying the problem to just one equation.
Solving Equations
Solving equations is a foundational skill essential for algebra. It involves finding the values of variables that make an equation true. In systems of equations—two or more equations sharing variables—there are several strategies:
- The addition (or elimination) method, which simplifies systems by reducing the number of variables in one equation.
- Substitution, which solves one equation for one variable and substitutes that result into another equation.
- Graphical methods, where equations are plotted to find points of intersection.