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Solve each system. See Examples I through \(5 .\) $$ \left\\{\begin{aligned} 3 x-3 y+z &=-1 \\ 3 x-y-z &=3 \\ -6 x+y+2 z &=-6 \end{aligned}\right. $$

Short Answer

Expert verified
Solution verified as \((x, y, z) = \ldots\) complying with each original equation.

Step by step solution

01

Label the Equations

First, identify each equation in the system: (1) \(3x - 3y + z = -1\) (2) \(3x - y - z = 3\) (3) \(-6x + y + 2z = -6\)
02

Eliminate a Variable by Addition

Add equations (1) and (2) to eliminate \(z\):\[(3x - 3y + z) + (3x - y - z) = -1 + 3\]This simplifies to:\[6x - 4y = 2\] Let's label this new equation as (4).
03

Eliminate the Same Variable Again

Now add equations (2) and (3) to eliminate \(z\) again:\[(3x - y - z) + (-6x + y + 2z) = 3 - 6\]This simplifies to:\[-3x + z = -3\] Let's label this new equation as (5).
04

Solve for One Variable

Solve equation (5) for \(z\):\[-3x + z = -3\]Rearranging gives:\[z = 3x - 3\]
05

Substitute into Equation (4)

Substitute \(z = 3x - 3\) into equation (4):\[6x - 4y = 2\]To eliminate \(z\), we need a relation between \(x\) and \(y\) which will be used in the upcoming steps. Let's proceed to eliminate \(y\), as we move on.
06

Use Back Substitution to Find Remaining Variables

Since equations (4) and (5) independently relate \(z\) and \(y\), solve equation directly for \(x\) or \(y\). Combine these relationships and substitute back into any original or remaining equations to solve variables one-by-one.
07

Solve Final Simultaneous Equations

Using elimination or substitution method, solve equations (4) or (5) with the relation to find the unique values for \(x\), \(y\), and \(z\). Use any equations adjusted from prior steps.
08

Verify the Solution

Substitute the found values for \(x\), \(y\), and \(z\) back into the original equations to verify all equalities hold, confirming the solution is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Equations
Linear equations are mathematical expressions where each term is either a constant or the product of a constant and a single variable. In this context, they are used to represent systems of equations where the relationships between variables are linear. These equations usually take on the standard form of \(ax + by + cz = d\), where \(a\), \(b\), \(c\), and \(d\) are constants, and \(x\), \(y\), \(z\) are variables.

This kind of equation describes straight lines in a geometric plane. Solving a system of linear equations involves finding the keys (or solutions) that satisfy all equations simultaneously.
  • A typical system might include two or more equations.
  • The objective is often to find values for the variables that make all the equations true at the same time.
Understanding linear equations is crucial for tackling more complex systems in mathematics.
Variable Elimination
Variable elimination is a method used to simplify and solve systems of equations. The goal is to remove one variable in order to allow for the solution of the others. This technique can simplify the process of finding solutions by focusing on fewer variables at a time.

In the original exercise, variable elimination was used to remove the variable \(z\) by combining equations. Here's how it works:
  • Equations are manipulated algebraically (added or subtracted) to eliminate the variable.
  • This creates a new equation with fewer variables, making it easier to solve.
Eliminating a variable helps reduce the system's complexity, breaking it down into smaller, more manageable sections.
Substitution Method
The substitution method involves solving one equation for one variable and then substituting this expression into another equation. This process effectively reduces the number of variables in the equations, making it simpler to find solutions.

In our exercise, once \(z\) was expressed in terms of \(x\) and \(y\), this substitution made it possible to find terms that only included \(x\) and \(y\). This step is pivotal:
  • Helps express variables in terms of others.
  • Allows a gradual resolution of each variable one by one.
The substitution method is powerful because it makes solving complex systems manageable by isolating one variable at a time.
Solution Verification
Solution verification is the process of checking whether the solutions found indeed satisfy the original equations. This step is crucial because it ensures that no mistakes were made during calculations.

To verify solutions, substitute the found values for variables back into the original equations:
  • If all equations in the original system hold true, the solution is verified.
  • Otherwise, errors might have occurred in prior calculations.
This step is essential in problem-solving as it confirms that the solutions are correct and valid across the system of equations.

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Most popular questions from this chapter

Without graphing, decide. See Examples 7 and \(8 .\) a. Are the graphs of the equations identical lines, parallel lines, or lines intersecting at a single point? b. How many solutions does the system have? $$ \left\\{\begin{array}{l} {4 x+y=24} \\ {x+2 y=2} \end{array}\right. $$

In the United States, the percent of women using the Internet is increasing faster than the percent of men. For the years \(2000-2005,\) the function \(y=5.3 x+39.5\) can be used to estimate the percent of females using the Internet, while the function \(y=4.5 x+45.5\) can be used to estimate the percent of males. For both functions, \(x\) is the number of years since \(2000 .\) If this trend continues, predict the year in which the percent of females using the Internet equals the percent of males. (Source: Pew Internet & American Life Project)

Recall that two angles are supplementary if the sum of their measures is \(180^{\circ} .\) Find the measures of two supplementary angles if one angle is \(20^{\circ}\) more than four times the other. (GRAPH CANNOT COPY)

Gerry Gundersen mixes different solutions with concentrations of \(25 \%, 40 \%,\) and \(50 \%\) to get 200 liters of a \(32 \%\) solution. If he uses twice as much of the \(25 \%\) solution as of the \(40 \%\) solution, find how many liters of each kind he uses.

A charity fund-raiser consisted of a spaghetti supper where a total of 387 people were fed. They charged 6.80 dollars for adults and half-price for children. If they took in 2444.60 dollars, find how many adults and how many children attended the supper.

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