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Find an equation of the line passing through each pair of points. Write the equation in the form \(A x+B y=C .\) See Example 5. $$ (-4,0) \text { and }(6,-1) $$

Short Answer

Expert verified
The equation of the line is \(x + 10y = -4\).

Step by step solution

01

Find the Slope

To find the slope (m) of the line passing through the two points (-4, 0) and (6, -1), use the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substitute the known values: \[ m = \frac{-1 - 0}{6 - (-4)} = \frac{-1}{10} \] So, the slope m is \(-\frac{1}{10}\).
02

Write the Point-Slope Form

Using the point-slope form of the equation of a line \( y - y_1 = m(x - x_1) \), substitute one of the points (-4, 0) and the slope \(-\frac{1}{10}\): \[ y - 0 = -\frac{1}{10}(x + 4) \] This simplifies to: \[ y = -\frac{1}{10}x - \frac{2}{5} \]
03

Convert to Standard Form

The standard form of the line is \(Ax + By = C\). Start from the equation \( y = -\frac{1}{10}x - \frac{2}{5} \) and rearrange it:\[ 10y = -x - 4 \] To put this in standard form, rearrange to \[ x + 10y = -4 \]
04

Verify the Equation

Confirm the line equation is correct by substituting the original points (-4, 0) and (6, -1) back into \(x + 10y = -4\). For (-4, 0): \(-4 + 10(0) = -4\) is true.For (6, -1): \(6 + 10(-1) = -4\) is also true.Both points satisfy the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point-Slope Form
The point-slope form is a useful tool when you know one point on a line and the slope of that line. It provides a straightforward way to express the equation of a line, making it an excellent starting point for further conversion into other formats. Generally, the formula looks like this:

\[ y - y_1 = m(x - x_1) \]

Where:
  • \( x_1, y_1 \) are the coordinates of the given point.
  • \( m \) is the slope of the line.
  • \( x \) and \( y \) are the variables.
In our exercise, we used the point \((-4,0)\) and the slope \(-\frac{1}{10}\) to write the equation in point-slope form. We substituted these into the equation like this:

\[ y - 0 = -\frac{1}{10}(x + 4) \]

Then, we simplified it to get:

\[ y = -\frac{1}{10}x - \frac{2}{5} \]

This form is particularly helpful when focusing on the relationship between slope and line orientation.
Standard Form of Linear Equation
The standard form of a linear equation is another fundamental way to describe a line algebraically. It typically appears as:

\[ Ax + By = C \]

Here, \( A \), \( B \), and \( C \) are integers and \( A \) should be non-negative. The equation helps clearly express a line without fractional coefficients, which can be advantageous for certain algebraic operations or integrations.
  • To convert the equation \( y = -\frac{1}{10}x - \frac{2}{5} \) into standard form, multiply through by 10 to clear the fraction, obtaining: \( 10y = -x - 4 \).
  • Then, rearrange and simplify it to get \( x + 10y = -4 \).
This equation now satisfies the standard format and is confirmed by checking that both original points, \((-4,0)\) and \(6,-1)\), validate it when substituted back.
Slope Calculation
Calculating the slope of a line is a fundamental concept in understanding linear functions. The slope \( m \) represents the tangent of the angle that a line makes with the positive x-axis. It indicates how steep the line is, and whether it is ascending, descending, or horizontal. To find the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\), use the formula:

\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

This formula calculates the 'rise over run' or the change in y over the change in x.
  • Substituting the points \((-4, 0)\) and \((6, -1)\), we get: \( \frac{-1 - 0}{6 - (-4)} = \frac{-1}{10} \).
  • This gives a negative slope, indicating the line descends from left to right.
Understanding how to calculate and interpret the slope is crucial for graphing lines and understanding their behavior relative to the x and y axes.

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