Chapter 3: Problem 25
Find an equation of each line with the given slope that passes through the given point. Write the equation in the form \(A x+B y=C .\) See Example 4. $$ m=-8 ;(-1,-5) $$
Short Answer
Expert verified
The equation is \( 8x + y = -13 \).
Step by step solution
01
Recall the point-slope form equation
The point-slope form of the equation of a line is given by \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line.
02
Substitute the given slope and point into the equation
We have been given the slope \( m = -8 \) and the point \( (-1, -5) \). Substituting these into the point-slope form, we get: \[ y - (-5) = -8(x - (-1)) \] which simplifies to: \[ y + 5 = -8(x + 1) \].
03
Simplify the equation
Now, distribute \(-8\) in the equation \( y + 5 = -8(x + 1) \):\[ y + 5 = -8x - 8 \] Simplify by subtracting 5 from both sides:\[ y = -8x - 13 \].
04
Convert to standard form
We need to rearrange the equation \( y = -8x - 13 \) into the standard form \( Ax + By = C \). Add \( 8x \) to both sides:\[ 8x + y = -13 \].This is the required equation in standard form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Point-Slope Form
The point-slope form of a linear equation is particularly useful when you know the slope of the line and at least one point through which the line passes. This form is given by the equation:
- \( y - y_1 = m(x - x_1) \)
- \( m \) is the slope of the line
- \((x_1, y_1)\) is a point on the line.
- \( y - (-5) = -8(x - (-1)) \)
- Simplifying to \( y + 5 = -8(x + 1) \)
Slope-Intercept Form
The slope-intercept form is one of the most popular forms of linear equations among students. It is written as:
For example, starting from \( y + 5 = -8x - 8 \), you can simplify it to:
- \( y = mx + b \)
- \( m \) is the slope of the line, just as in other forms
- \( b \) is the y-intercept, which is the point where the line crosses the y-axis
For example, starting from \( y + 5 = -8x - 8 \), you can simplify it to:
- \( y = -8x - 13 \)
Standard Form
The standard form of a linear equation is a neat and organized way of presenting a line's equation, especially useful when you want to highlight both the x and y coefficients. The standard form is expressed as:
To convert from the slope-intercept form to standard form, you rearrange the equation by getting all variables on the left-hand side. From the slope-intercept form \( y = -8x - 13 \), you add \( 8x \) to both sides:
- \( Ax + By = C \)
To convert from the slope-intercept form to standard form, you rearrange the equation by getting all variables on the left-hand side. From the slope-intercept form \( y = -8x - 13 \), you add \( 8x \) to both sides:
- \( 8x + y = -13 \)