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Solve each inequality. Graph the solution set and write it in interval notation. $$ 1<4+2 x \leq 7 $$

Short Answer

Expert verified
\(-\frac{3}{2} < x \leq \frac{3}{2}\) in interval notation is \((-\frac{3}{2}, \frac{3}{2}]\).

Step by step solution

01

Break Down the Inequality

The given inequality is: \(1 < 4 + 2x \leq 7\). This is a compound inequality that comprises two parts: \(1 < 4 + 2x\) and \(4 + 2x \leq 7\). Our goal is to solve these inequalities separately and then combine their solutions.
02

Solve the First Inequality

Let's solve the first part \(1 < 4 + 2x\). Subtract 4 from both sides to isolate the term with \(x\): \[1 - 4 < 2x \ -3 < 2x\]Now, divide both sides by 2 to solve for \(x\):\[-\frac{3}{2} < x\]
03

Solve the Second Inequality

Now, solve the second part \(4 + 2x \leq 7\). Subtract 4 from both sides:\[ 4 + 2x - 4 \leq 7 - 4 \ 2x \leq 3\]Divide both sides by 2 to solve for \(x\):\[x \leq \frac{3}{2}\]
04

Combine the Solutions

The solutions from Steps 2 and 3 result in the compound inequality:\[-\frac{3}{2} < x \leq \frac{3}{2}\]This can be read as \(x\) is greater than \(-\frac{3}{2}\) and less than or equal to \(\frac{3}{2}\).
05

Represent the Solution in Interval Notation

The interval notation for \(-\frac{3}{2} < x \leq \frac{3}{2}\) is:\[(-\frac{3}{2}, \frac{3}{2}]\]
06

Graph the Solution Set

To graph the solution \((-\frac{3}{2}, \frac{3}{2}]\), draw a number line. Plot an open circle at \(-\frac{3}{2}\) to indicate it is not included, and a closed circle at \(\frac{3}{2}\) to indicate it is included. Shade the region between the two points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Compound Inequalities
Compound inequalities are a way of expressing two inequalities that are often related to each other. Instead of solving them one by one, we take a look at them as a package. In our exercise, we have the compound inequality:
1. \(1 < 4 + 2x\)2. \(4 + 2x \leq 7\)
The goal of compound inequalities is to find a range of values for the variable, which in this case is \(x\), that satisfy all parts of the inequality simultaneously.
  • Step 2 helps us solve the first part \(1 < 4 + 2x\) by simplifying it to \(-\frac{3}{2} < x\).
  • Step 3 helps with the second part \(4 + 2x \leq 7\) simplifying it to \(x \leq \frac{3}{2}\).

We combine these solutions into one compound inequality: \(-\frac{3}{2} < x \leq \frac{3}{2}\). This tells us where \(x\) can safely exist between these two numbers, adhering to all parts of the inequality. It’s like setting boundaries for \(x\) on a number line!
Interval Notation: A Compact Solution
Once we have a compound inequality, we can express its solutions in a compact form known as interval notation. This notation provides a clear and concise way of showing which numbers fit our solution.
To understand this, let's look again at the solution we've found: \(-\frac{3}{2} < x \leq \frac{3}{2}\).
  • The round bracket \((-\frac{3}{2},\) signifies that \(-\frac{3}{2}\) is not included in the solution.
  • The square bracket \(\frac{3}{2}]\), indicates that \(\frac{3}{2}\) is included.

Therefore, the interval \((-\frac{3}{2}, \frac{3}{2}]\) effectively summarizes all possible values of \(x\) that satisfy our compound inequality. It's like a shorthand for saying: "All numbers more than \(-\frac{3}{2}\) and up to and including \(\frac{3}{2}\) are in the solution set."
Graphing Inequalities Made Easy
Graphing inequalities on a number line is a visual way to understand the solution set. It helps in clearly identifying which numbers are part of the solution and which are not.
To graph \((-\frac{3}{2}, \frac{3}{2}]\), follow these simple steps:
  • Draw a number line.
  • At \(-\frac{3}{2}\), place an open circle. This indicates \(-\frac{3}{2}\) isn't part of the solution.
  • At \(\frac{3}{2}\), place a closed circle showing \(\frac{3}{2}\) is included in the solution set.
  • Shade the area between the two points. This shaded region represents all the values that satisfy the inequality.

By graphing, you create a handy visual that makes it easy for anyone to quickly see the range of possible solutions. It's like a map that tells you where the values of \(x\) fit according to the compound inequality.

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