Chapter 14: Problem 24
Use the binomial formula to expand each binomial. \((3 m+n)^{4}\)
Short Answer
Expert verified
The expansion of \((3m + n)^4\) is \(81m^4 + 108m^3n + 54m^2n^2 + 12mn^3 + n^4\).
Step by step solution
01
Understand the Binomial Expansion Formula
The binomial expansion formula is given by \[(a + b)^n = \sum_{k=0}^{n} {n\choose k} \cdot a^{n-k} \cdot b^k\]where \({n \choose k}\) is the binomial coefficient calculated as \(\frac{n!}{k!(n-k)!}\). In this expression, \(a = 3m\), \(b = n\), and \(n = 4\).
02
Calculate Binomial Coefficients
Use the formula for binomial coefficients to find the values for each term:\[{4 \choose 0} = 1, \quad {4 \choose 1} = 4, \quad {4 \choose 2} = 6, \quad {4 \choose 3} = 4, \quad {4 \choose 4} = 1\]
03
Write and Simplify Each Term
Find each term of the expansion by applying the binomial formula:- First term: \( {4 \choose 0} \cdot (3m)^4 \cdot n^0 = 1 \cdot 81m^4 \cdot 1 = 81m^4 \)- Second term: \( {4 \choose 1} \cdot (3m)^3 \cdot n^1 = 4 \cdot 27m^3 \cdot n = 108m^3n \)- Third term: \( {4 \choose 2} \cdot (3m)^2 \cdot n^2 = 6 \cdot 9m^2 \cdot n^2 = 54m^2n^2 \)- Fourth term: \( {4 \choose 3} \cdot (3m)^1 \cdot n^3 = 4 \cdot 3m \cdot n^3 = 12mn^3 \)- Fifth term: \( {4 \choose 4} \cdot (3m)^0 \cdot n^4 = 1 \cdot 1 \cdot n^4 = n^4 \)
04
Construct Final Expansion
Compile all the terms to write the complete expansion:\[(3m + n)^4 = 81m^4 + 108m^3n + 54m^2n^2 + 12mn^3 + n^4\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Theorem
The binomial theorem is a powerful tool in algebra used to expand expressions raised to a power. Imagine you have a binomial, which means an expression with two terms like \((a + b)^n\), and you want to expand it into a polynomial with several terms. The binomial theorem gives you a formula to do just that:
- \((a + b)^n = \sum_{k=0}^{n} {n\choose k} \cdot a^{n-k} \cdot b^k\)
Binomial Coefficient
Binomial coefficients are the numbers that arise in the expansion of a binomial raised to a power. You see them in \({n\choose k}\), which is shorthand for 'n choose k' and is calculated using the formula:
- \({n \choose k} = \frac{n!}{k!(n-k)!}\)
- \({4 \choose 0} = 1\)
- \({4 \choose 1} = 4\)
- \({4 \choose 2} = 6\)
- \({4 \choose 3} = 4\)
- \({4 \choose 4} = 1\)
Polynomial Expansion
Polynomial expansion utilizes the binomial theorem to expand expressions such as \((3m + n)^4\) into a sum of terms. Each term in the expanded form is a product involving powers of \(3m\) and \(n\), multiplied by the appropriate binomial coefficient.Let's break it down into the steps used when expanding \((3m + n)^4\):
- Start by determining the binomial coefficients. For our example, they are 1, 4, 6, 4, and 1.
- Form terms using these coefficients by applying them to products of \((3m)^{4-k}\) and \(n^k\), for each \(k\) from 0 to 4.
- Simplify each term by calculating the powers and multiplying by the coefficients.
- Combine all of the simplified terms to get the final polynomial expression.