Chapter 14: Problem 15
Write the first five terms of each sequence whose general term is given. $$ a_{n}=(-1)^{n} n^{2} $$
Short Answer
Expert verified
The first five terms are -1, 4, -9, 16, -25.
Step by step solution
01
Understanding the General Term
The general term given is \( a_n = (-1)^n n^2 \). This represents a sequence where each term is generated by substituting integers starting from 1 into \( n \). The term \((-1)^n\) will alternate each term between positive and negative, as \((-1)^n\) equals -1 for odd n and 1 for even n.
02
Calculate the First Term
To find the first term \(a_1\), substitute \(n = 1\) into the general term: \[ a_1 = (-1)^1 \times 1^2 = -1. \] So, the first term is \(-1\).
03
Calculate the Second Term
Substitute \(n = 2\) into the general term to find \(a_2\): \[ a_2 = (-1)^2 \times 2^2 = 1 \times 4 = 4. \] Thus, the second term is \(4\).
04
Calculate the Third Term
Next, substitute \(n = 3\) for the third term: \[ a_3 = (-1)^3 \times 3^2 = -1 \times 9 = -9. \] So, the third term is \(-9\).
05
Calculate the Fourth Term
For the fourth term \(a_4\), substitute \(n = 4\): \[ a_4 = (-1)^4 \times 4^2 = 1 \times 16 = 16. \] Thus, the fourth term is \(16\).
06
Calculate the Fifth Term
Finally, substitute \(n = 5\) for the fifth term: \[ a_5 = (-1)^5 \times 5^2 = -1 \times 25 = -25. \] Therefore, the fifth term is \(-25\).
07
Write the First Five Terms
The first five terms of the sequence, based on the calculations from previous steps, are \(-1, 4, -9, 16, -25\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Alternating Series
An alternating series is a sequence of numbers where the signs of the terms alternate. This means the series has a pattern of positive and negative terms. Such a series is commonly represented as \[ \sum_{n=1}^{\infty} (-1)^n a_n \] where \[ (-1)^n \] dictates the sign of each term:
- When \( n \) is odd, \( (-1)^n \) is -1, making the term negative.
- When \( n \) is even, \( (-1)^n \) is 1, making the term positive.
General Term in Sequences
The general term in a sequence provides a formula that defines every term in the sequence as a function of its position (usually denoted as \( n \)). It acts as a key to generating any term in the sequence without having to list all the previous terms. For the sequence given by the general term\[ a_n = (-1)^n n^2 \]the formula tells us:
- The position \( n \) is used to determine both the sign and the magnitude of the term.
- \( n^2 \) computes the square of the position, defining the size of each term.
- \((-1)^n\) alters each term's sign depending on whether \( n \) is odd or even. This determines the alternating nature.
Substitution Method
The substitution method is a straightforward approach to finding the terms of a sequence or a formula. In this method, you replace the variable in an expression or formula with specific numbers to calculate the desired values. In the context of our sequence:
- The formula is \( a_n = (-1)^n n^2 \).
- By substituting \( n \) with integers like 1, 2, 3, 4, and 5, you generate the respective sequence terms.