/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Sketch the graph of each equatio... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of each equation. \(\frac{x^{2}}{16}+\frac{y^{2}}{9}=1\)

Short Answer

Expert verified
The graph is a horizontally oriented ellipse with vertices at (4, 0) and (-4, 0), and co-vertices at (0, 3) and (0, -3).

Step by step solution

01

Identify the Type of Conic Section

The given equation \(\frac{x^{2}}{16}+\frac{y^{2}}{9}=1\) is of the form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), which is the standard form of an ellipse. Here, \(a^2 = 16\) and \(b^2 = 9\).
02

Determine the Orientation

For ellipses of the form \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\), if \(a > b\), the ellipse is oriented horizontally. Since \(a=4\sqrt{4}\) and \(b=3\sqrt{3}\), and \(4 > 3\), the ellipse is horizontal.
03

Calculate the Vertices

The vertices of a horizontal ellipse are located at \((\pm a, 0)\). Since \(a=4\), the vertices are \((4, 0)\) and \((-4, 0)\).
04

Calculate the Co-vertices

The co-vertices of a horizontal ellipse are located at \((0, \pm b)\). Since \(b=3\), the co-vertices are \((0, 3)\) and \((0, -3)\).
05

Plot the Vertices and Co-vertices

On the coordinate plane, plot the vertices at \((4, 0)\) and \((-4, 0)\), and the co-vertices at \((0, 3)\) and \((0, -3)\). These points help in sketching the shape of the ellipse.
06

Sketch the Ellipse

Draw a smooth, oval-shaped curve passing through all plotted points (vertices and co-vertices), ensuring the ellipse is wider along the horizontal axis than the vertical axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Conic sections are the shapes you get when you slice a cone in different ways. They include circles, ellipses, parabolas, and hyperbolas. Each type of conic section has its unique properties and equations.

Ellipses are particularly interesting because they resemble stretched circles. They are defined by the equation \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Depending on how you slice the cone, the ellipse can look more like a squashed circle or an elongated oval.

Conic sections have many applications in the real world, from planetary orbits to engineering designs, making them crucial in both mathematics and physics.
Ellipse Orientation
The orientation of an ellipse is determined by comparing the values of \(a^2\) and \(b^2\) in its equation. An ellipse with a larger \(a^2\) value than \(b^2\) is oriented horizontally. This means it will be wider along the x-axis. Conversely, if \(b^2\) is larger than \(a^2\), the ellipse is oriented vertically, making it taller along the y-axis.

In the exercise, the ellipse equation is \(\frac{x^2}{16} + \frac{y^2}{9} = 1\). Here, \(a^2\) is 16 and \(b^2\) is 9. Since 16 is greater than 9, the ellipse is oriented horizontally. This affects how we plot and visualize the ellipse on the graph. It will spread more along the horizontal axis.
Ellipse Vertices
Vertices are the points on an ellipse that lie along the major axis, which is the longer diameter of the ellipse. For a horizontal ellipse, these points are found at \((\pm a, 0)\). Here, \(a\) is calculated as the square root of \(a^2\).

In this case, \(a^2 = 16\) so \(a = 4\). This means the vertices of the ellipse are located at \((4, 0)\) and \((-4, 0)\). These points are crucial for sketching the ellipse, as they denote its widest points on the x-axis.

Co-vertices are found along the minor axis, at \((0, \pm b)\). Since \(b^2 = 9\), \(b = 3\), placing the co-vertices at \((0, 3)\) and \((0, -3)\). These help define the height of the ellipse along the y-axis.
Graphing Ellipses
To graph an ellipse, you start by plotting its vertices and co-vertices, which establish the shape's framework. For our ellipse, we plot the vertices \((4, 0)\), \((-4, 0)\) and the co-vertices \((0, 3)\), \((0, -3)\).

Next, we draw a smooth, oval-shaped curve connecting these points. Ensure the ellipse is wider along its horizontal length, as indicated by the given equation \(\frac{x^2}{16} + \frac{y^2}{9} = 1\), which specifies a horizontal orientation.

When sketching, make sure the shape touches all plotted points, ensuring it is symmetric about both the x and y axes. A well-drawn ellipse reflects the true geometric nature as defined by its equation, perfect for any mathematical exercise or real-world application.

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Most popular questions from this chapter

Cindy Brown, an architect, is drawing plans on grid paper for a circular pool with a fountain in the middle. The paper is marked off in centimeters, and each centimeter represents 1 foot. On the paper, the diameter of the "pool" is 20 centimeters, and "fountain" is the point \((0,0)\) a. Sketch the architect's drawing. Be sure to label the axes. b. Write an equation that describes the circular pool. c. Cindy plans to place a circle of lights around the fountain such that each light is 5 feet from the fountain. Write an equation for the circle of lights and sketch the circle on your drawing.

Recall that in business, a demand function expresses the quantity of a commodity demanded as a function of the commodity's unit price. \(A\) supply function expresses the quantity of a commodity supplied as a function of the commodity's unit price. When the quantity produced and supplied is equal to the quantity demanded, then we have what is called market equilibrium. (Graph can't copy) The demand function for a certain compact disc is given by the function $$ p=-0.01 x^{2}-0.2 x+9 $$ and the corresponding supply function is given by $$ p=0.01 x^{2}-0.1 x+3 $$ where \(p\) is in dollars and \(x\) is in thousands of units. Find the equilibrium quantity and the corresponding price by solving the system consisting of the two given equations.

The graph of each equation is a parabola. Find the vertex of the parabola and sketch its graph. See Examples I through 4. $$ x=3 y^{2} $$

Discuss how graphing a linear inequality such as \(x+y<9\) is similar to graphing a nonlinear inequality such as \(x^{2}+y^{2}<9\)

Sketch the graph of each equation. If the graph is a parabola, find irs vertex. If the graph is a circle, find its center and radius. $$x=-3 y^{2}+30 y$$

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