Chapter 11: Problem 76
Find the maximum or minimum value of each function. Approximate to two decimal places. $$ f(x)=-5.2 x^{2}-3.8 x+5.1 $$
Short Answer
Expert verified
The maximum value of the function is approximately 3.02.
Step by step solution
01
Identify the Quadratic Function Form
The given function is a quadratic function, which can be expressed in the general form of \( f(x) = ax^2 + bx + c \). Here, \( a = -5.2 \), \( b = -3.8 \), and \( c = 5.1 \). Since \( a < 0 \), the parabola opens downwards, indicating that the function has a maximum point.
02
Find the Vertex Formula
To find the maximum or minimum value of the quadratic function, use the vertex formula \( x = -\frac{b}{2a} \). This formula provides the x-coordinate of the vertex, which is the point where the maximum or minimum value occurs for a quadratic function.
03
Calculate the x-coordinate of the Vertex
Substitute the given values of \( a \) and \( b \) into the vertex formula: \[ x = -\frac{-3.8}{2(-5.2)} = -\frac{-3.8}{-10.4} = \frac{3.8}{10.4} \approx 0.365 \]This calculation shows the x-coordinate of the vertex is approximately \( 0.365 \).
04
Substitute x into the Function
Now that we have the x-coordinate, substitute it back into the function to find the y-coordinate (the actual maximum value):\[ f(0.365) = -5.2 (0.365)^2 - 3.8(0.365) + 5.1 \] Calculate each term:- \( -5.2 \times 0.365^2 \approx -0.693 \) - \( -3.8 \times 0.365 \approx -1.387 \) And then add them along with 5.1:\[ f(0.365) \approx -0.693 - 1.387 + 5.1 = 3.02 \]
05
Determine the Vertex Value
The y-coordinate of the vertex gives the maximum value of the function. From the previous calculation, this maximum value is approximately \( 3.02 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Formula
The Vertex Formula is essential in finding the peak of a quadratic function. For any quadratic function written as \( f(x) = ax^2 + bx + c \), the vertex formula is \( x = -\frac{b}{2a} \). This formula allows us to locate the x-coordinate of the vertex, which is the highest or lowest point on a parabola. It helps indicate where the function reaches its extremum, whether a maximum or minimum value.
In our example, the quadratic function is \( f(x) = -5.2x^2 - 3.8x + 5.1 \). By identifying the coefficients, we have \( a = -5.2 \), \( b = -3.8 \), and \( c = 5.1 \).
Using the vertex formula, we substitute the values into \( x = -\frac{b}{2a} \):
This x-coordinate of the vertex provides the critical point to find the largest or smallest y-value of the function.
In our example, the quadratic function is \( f(x) = -5.2x^2 - 3.8x + 5.1 \). By identifying the coefficients, we have \( a = -5.2 \), \( b = -3.8 \), and \( c = 5.1 \).
Using the vertex formula, we substitute the values into \( x = -\frac{b}{2a} \):
- \( x = -\frac{-3.8}{2(-5.2)} = \frac{3.8}{10.4} \)
- \( x \approx 0.365 \) after simplifying the arithmetic calculation
This x-coordinate of the vertex provides the critical point to find the largest or smallest y-value of the function.
Maximum and Minimum Values
Quadratic functions are known for their critical points, which are crucial to understanding their behavior. Whether the parabola represents a hill or a valley, it has either a maximum or a minimum value.
The coefficient \( a \) in the quadratic equation \( f(x) = ax^2 + bx + c \) dictates the direction of the parabola:
In this case, \( a = -5.2 \), meaning the parabola opens downward, so we identify a maximum value. Once we have the x-coordinate from the vertex formula, substitute it back into the function to determine the maximum y-value:
This calculation shows that the maximum value of the function is about \(3.02\).
The coefficient \( a \) in the quadratic equation \( f(x) = ax^2 + bx + c \) dictates the direction of the parabola:
- If \( a > 0 \), the parabola opens upwards, featuring a minimum value.
- If \( a < 0 \), it opens downwards, presenting a maximum value.
In this case, \( a = -5.2 \), meaning the parabola opens downward, so we identify a maximum value. Once we have the x-coordinate from the vertex formula, substitute it back into the function to determine the maximum y-value:
- \( f(0.365) = -5.2 \times (0.365)^2 - 3.8 \times 0.365 + 5.1 \)
- Calculate each term: \( -5.2 \times 0.133225 \approx -0.693 \) and \( -3.8 \times 0.365 \approx -1.387 \)
- Add \(-0.693\), \(-1.387\), and \(5.1\): Approximate maximum is \(\approx 3.02\)
This calculation shows that the maximum value of the function is about \(3.02\).
Parabola
A parabola is a u-shaped curve that describes the graph of a quadratic function. The orientation of a parabola—whether it opens up or down—is determined by the sign of the leading coefficient \( a \) in the function \( f(x) = ax^2 + bx + c \).
Some important characteristics of a parabola include:
In this function, \( f(x) = -5.2x^2 - 3.8x + 5.1 \), the leading term \( -5.2 \) tells us that the parabola opens downwards. This implies that the function has a maximum vertex point. Understanding the shape and properties of a parabola helps us predict and interpret the outcomes of applying quadratic functions to real-world situations.
Some important characteristics of a parabola include:
- **Vertex:** The peak or trough of the parabola, where the quadratic reaches its maximum or minimum value.
- **Axis of Symmetry:** A line that passes through the vertex, dividing the parabola into two mirror-image halves.
- **Direction of Opening:** Determined by \( a \); if \( a > 0 \), it opens upwards, and if \( a < 0 \), it opens downwards.
In this function, \( f(x) = -5.2x^2 - 3.8x + 5.1 \), the leading term \( -5.2 \) tells us that the parabola opens downwards. This implies that the function has a maximum vertex point. Understanding the shape and properties of a parabola helps us predict and interpret the outcomes of applying quadratic functions to real-world situations.