Chapter 11: Problem 72
Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find the \(y\) -intercept, approximate the \(x\) -intercepts to one decimal place, and sketch the graph. $$ f(x)=2 x^{2}+4 x-1 $$
Short Answer
Expert verified
Vertex: (-1, -3); Opens upward; y-intercept: (0, -1); x-intercepts: (-2.4, 0.4).
Step by step solution
01
Identify the Standard Form and Coefficients
The quadratic function is given as \( f(x) = 2x^2 + 4x - 1 \). It is in the standard form \( ax^2 + bx + c \), where \( a = 2 \), \( b = 4 \), and \( c = -1 \).
02
Determine the Direction of Opening
The coefficient \( a \) of the \( x^2 \) term is 2, which is positive. Therefore, the graph of the function opens upward.
03
Find the Vertex
The vertex of a parabola in standard form is found using the formula \( x = -\frac{b}{2a} \). Substituting the values, \( x = -\frac{4}{2 \times 2} = -1 \). To find the \( y \)-coordinate of the vertex, substitute \( x = -1 \) back into the function: \( f(-1) = 2(-1)^2 + 4(-1) - 1 = -3 \). Thus, the vertex is \((-1, -3)\).
04
Find the y-intercept
The \( y \)-intercept is found by setting \( x = 0 \) in the equation \( f(x) = 2x^2 + 4x - 1 \). This gives \( f(0) = -1 \). Thus, the \( y \)-intercept is at \( (0, -1) \).
05
Approximate the x-intercepts
To find the \( x \)-intercepts, set \( f(x) = 0 \). This gives the equation \( 2x^2 + 4x - 1 = 0 \). Using the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), we have \( x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 2 \cdot (-1)}}{2 \cdot 2} \), which simplifies to \( x = \frac{-4 \pm \sqrt{24}}{4} \). This gives \( x = -2.4 \) and \( x = 0.4 \).
06
Sketch the Graph
Plot the vertex \((-1, -3)\), the \( y \)-intercept \((0, -1)\), and the \( x \)-intercepts \((-2.4, 0)\) and \((0.4, 0)\). Draw a parabola that opens upwards through these points.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
In the context of quadratic functions, the vertex is an important point on the graph of a parabola. It represents either the highest or lowest point, depending on whether the parabola opens upward or downward. For a function given in the form of \( ax^2 + bx + c \), the formula to find the x-coordinate of the vertex is \( x = -\frac{b}{2a} \).
Once the x-coordinate is known, substitute it back into the function to find the y-coordinate. This will give the complete vertex point \((x, y)\).
In our problem, we used the function \( f(x) = 2x^2 + 4x - 1 \), with coefficients \( a = 2 \), \( b = 4 \), and \( c = -1 \).
This led to the vertex calculation \( x = -\frac{4}{4} = -1 \). Then, by substituting \( x = -1 \), we got the vertex at \((-1, -3)\).
Remembering the vertex is crucial in understanding the basic shape and position of the parabola on a graph.
Once the x-coordinate is known, substitute it back into the function to find the y-coordinate. This will give the complete vertex point \((x, y)\).
In our problem, we used the function \( f(x) = 2x^2 + 4x - 1 \), with coefficients \( a = 2 \), \( b = 4 \), and \( c = -1 \).
This led to the vertex calculation \( x = -\frac{4}{4} = -1 \). Then, by substituting \( x = -1 \), we got the vertex at \((-1, -3)\).
Remembering the vertex is crucial in understanding the basic shape and position of the parabola on a graph.
X-Intercepts of Quadratics
Finding the x-intercepts of a quadratic function involves determining the points where the graph crosses the x-axis. These are the solutions to the equation \( f(x) = 0 \).
For a quadratic equation in standard form \( ax^2 + bx + c = 0 \), the quadratic formula can be used to find the x-intercepts:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
In our example problem, this calculation was applied to \( 2x^2 + 4x - 1 = 0 \), with \( a = 2 \), \( b = 4 \), and \( c = -1 \).
The discriminant part \( \sqrt{b^2 - 4ac} = \sqrt{16 + 8} = \sqrt{24} \) helps to estimate the number and type of roots.
This yields two x-intercepts after solving: \( x = -2.4 \) and \( x = 0.4 \).
These intercepts are useful for sketching the complete graph, showing where the parabola crosses the x-axis.
For a quadratic equation in standard form \( ax^2 + bx + c = 0 \), the quadratic formula can be used to find the x-intercepts:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
In our example problem, this calculation was applied to \( 2x^2 + 4x - 1 = 0 \), with \( a = 2 \), \( b = 4 \), and \( c = -1 \).
The discriminant part \( \sqrt{b^2 - 4ac} = \sqrt{16 + 8} = \sqrt{24} \) helps to estimate the number and type of roots.
This yields two x-intercepts after solving: \( x = -2.4 \) and \( x = 0.4 \).
These intercepts are useful for sketching the complete graph, showing where the parabola crosses the x-axis.
Graphing Parabolas
Graphing a parabola involves plotting several key points derived from the quadratic function and connecting them with a smooth curve. These points typically include:
After plotting these points, draw a smooth curve that passes through them. Ensure the curve is symmetric around the line \( x = -\frac{b}{2a} \). This symmetry helps maintain the accuracy of the sketch.
In the example, the parabola opens upward, showing a minimum at the vertex \((-1, -3)\), with x-intercepts at \(-2.4, 0.4\) and a y-intercept at \(0, -1\).
- The vertex, which provides a central reference point for the shape of the graph.
- The x-intercepts, indicating where the graph crosses the x-axis.
- The y-intercept, found by setting \( x = 0 \), which gives a point where the graph crosses the y-axis.
After plotting these points, draw a smooth curve that passes through them. Ensure the curve is symmetric around the line \( x = -\frac{b}{2a} \). This symmetry helps maintain the accuracy of the sketch.
In the example, the parabola opens upward, showing a minimum at the vertex \((-1, -3)\), with x-intercepts at \(-2.4, 0.4\) and a y-intercept at \(0, -1\).
Quadratic Formula
The quadratic formula is a powerful algebraic tool used to find the roots of any quadratic equation of the form \( ax^2 + bx + c = 0 \). Regardless of whether the roots are real or complex, the quadratic formula provides solutions systematically.
The formula is stated as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here:
This formula not only aids in finding roots but also informs graph interpretation and geometric properties of the quadratic.
The formula is stated as:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here:
- \( b^2 - 4ac \) is known as the discriminant.
- The discriminant determines the nature of the roots. If it's positive, there are two distinct real roots. Zero means exactly one real root (a double root), while a negative discriminant indicates complex roots.
This formula not only aids in finding roots but also informs graph interpretation and geometric properties of the quadratic.