Chapter 11: Problem 61
Sketch the graph of each function. See Section 11.5 $$ f(x)=3(x-4)^{2}+1 $$
Short Answer
Expert verified
The graph of \(f(x)=3(x-4)^{2}+1\) is a parabola opening upwards with vertex at \((4, 1)\), narrower than the standard \(x^2\) parabola.
Step by step solution
01
Identify the Base Function
The base function here is the quadratic function \(f(x) = x^2\). The given function is a transformation of this base function.
02
Determine the Vertex Form
The function \(f(x) = 3(x-4)^2 + 1\) is already in the vertex form \(a(x-h)^2 + k\), where \(a = 3\), \(h = 4\), and \(k = 1\).
03
Locate the Vertex
The vertex \((h, k)\) of the parabola is \((4, 1)\). This is the lowest point on the graph since \(a > 0\) indicating the parabola opens upwards.
04
Determine the Direction of the Parabola
Since the coefficient \(a = 3\) is positive, the parabola opens upwards.
05
Determine the Stretch Factor
The value of \(a = 3\) affects the rate at which the parabola widens. A value greater than 1 indicates the parabola is narrower than the standard \(x^2\) parabola.
06
Sketch the Graph
Plot the vertex at \((4, 1)\). Use the fact that the parabola is narrower and opens upwards to plot additional points. For example, calculate \(f(x)\) at \(x = 3\) and \(x = 5\) to find additional points like \((3, 4)\) and \((5, 4)\). Connect these points smoothly to form a parabola.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Form
A quadratic function in vertex form is especially helpful when sketching graphs.
It allows you to easily identify the key features of the function. The vertex form of a quadratic is given by \[ f(x) = a(x-h)^2 + k \] where:
In our exercise, the function \(3(x-4)^2+1\) shows the vertex at \((4, 1)\). This gives you a starting point for your graph.
It allows you to easily identify the key features of the function. The vertex form of a quadratic is given by \[ f(x) = a(x-h)^2 + k \] where:
- \( a \): a constant that affects the width and direction of the parabola.
- \( h \): the x-coordinate of the vertex.
- \( k \): the y-coordinate of the vertex.
In our exercise, the function \(3(x-4)^2+1\) shows the vertex at \((4, 1)\). This gives you a starting point for your graph.
Parabola
Parabolas are a type of curve that are symmetric and have a characteristic U-shape.
In the case of quadratic functions, the graph of the function is always a parabola. Depending on the value of \( a \) in the equation, the parabola can either open upwards or downwards:
Besides the direction, \( a \) also affects how wide the parabola opens. When \( \vert a \vert > 1 \), the parabola becomes narrower than the standard \( x^2 \) parabola. In contrast, when \( \vert a \vert < 1 \), the parabola becomes wider.
This means our parabola, with \( a = 3 \), will be narrower than the usual \( x^2 \) graph.
In the case of quadratic functions, the graph of the function is always a parabola. Depending on the value of \( a \) in the equation, the parabola can either open upwards or downwards:
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), the parabola opens downwards.
Besides the direction, \( a \) also affects how wide the parabola opens. When \( \vert a \vert > 1 \), the parabola becomes narrower than the standard \( x^2 \) parabola. In contrast, when \( \vert a \vert < 1 \), the parabola becomes wider.
This means our parabola, with \( a = 3 \), will be narrower than the usual \( x^2 \) graph.
Transformations
Understanding transformations of the base function \( f(x) = x^2 \) is crucial for graphing more complex quadratic functions.
Transformations include shifting, stretching, or reflecting the graph. For our equation \( f(x) = 3(x-4)^2 + 1 \), transformations play a key role:
They are easy to apply when the parabola is in vertex form, enabling quick and efficient graphing.
Transformations include shifting, stretching, or reflecting the graph. For our equation \( f(x) = 3(x-4)^2 + 1 \), transformations play a key role:
- **Horizontal Shift**: The expression \((x-4)\) means the graph shifts 4 units to the right.
- **Vertical Shift**: The \(+1\) at the end of the equation indicates a shift 1 unit upwards.
- **Vertical Stretch**: The coefficient \(3\) makes the parabola narrower compared to the regular parabola \( x^2 \), stretching it vertically.
They are easy to apply when the parabola is in vertex form, enabling quick and efficient graphing.