Chapter 11: Problem 49
Solve. \(p^{4}-p^{2}-20=0\)
Short Answer
Expert verified
The solutions for \(p\) are \(p = \pm\sqrt{5}\).
Step by step solution
01
Identify substitution
The expression is a quadratic in terms of \(p^2\). Let's use the substitution \(x = p^2\). This gives us \(x^2 = (p^2)^2 = p^4\).
02
Substitute and rewrite the equation
Substitute \(x = p^2\) into the equation: \(x^2 - x - 20 = 0\). Now, we need to solve this quadratic equation for \(x\).
03
Solve the quadratic
Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) where \(a = 1\), \(b = -1\), and \(c = -20\). Substitute to get \(x = \frac{1 \pm \sqrt{1 + 80}}{2} = \frac{1 \pm \sqrt{81}}{2}\).
04
Calculate the roots of the quadratic
Simplify \(\sqrt{81}\) which equals 9. Therefore, the roots are \(x = \frac{1 + 9}{2} = 5\) and \(x = \frac{1 - 9}{2} = -4\).
05
Reverse substitution
Recall substitution \(x = p^2\). Hence, \(p^2 = 5\) or \(p^2 = -4\).
06
Solve for \(p\)
For \(p^2 = 5\), \(p = \pm\sqrt{5}\). For \(p^2 = -4\), there are no real solutions since the square of a real number cannot be negative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic formula
The quadratic formula is a powerful tool for solving quadratic equations of the form \( ax^2 + bx + c = 0 \). It's given by the formula:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula allows you to find the values of \(x\) that satisfy the equation. Here's how it works:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This formula allows you to find the values of \(x\) that satisfy the equation. Here's how it works:
- a, b, and c are coefficients from your equation.
- The expression under the square root, \(b^2 - 4ac\), is called the discriminant.
- The discriminant tells you about the nature of the roots—whether they are real or complex.
reverse substitution
Reverse substitution is used to revert back to the original variable after solving a transformed equation. In our problem, we first substituted \(p^2 = x\) to simplify the equation from a quartic to a quadratic form. Here's how reverse substitution comes into play:
- Initially, transform \(p^4 - p^2 - 20 = 0\) into a simpler quadratic form: \(x^2 - x - 20 = 0\).
- After solving \(x^2 - x - 20 = 0\) and finding \(x = 5\) or \(x = -4\), replace \(x\) again with \(p^2\) to determine the values of \(p\).
real solutions
Real solutions in the context of quadratic equations refer to the solutions where the square root component in the quadratic formula yields a real number. For a solution to be real, the discriminant \(b^2 - 4ac\) in the quadratic formula must be greater than or equal to zero:
- If \( b^2 - 4ac > 0\), there are two distinct real solutions.
- If \( b^2 - 4ac = 0\), there is one real solution (a repeated root).
- If \( b^2 - 4ac < 0\), the solutions are complex and not real.